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At 298 K, the limiting molar conductivity of a weak monobasic acid is 4 x 102 S cm2 mol-1. At 298 K, for an aqueous solution of the acid, the degree of dissociation is  and the molar conductivity is y x 102 S cm2 mol-1. At 298 K, upon 20 times dilution with water, the molar conductivity of the solution becomes 3y x 102 S cm2 mol-1.
Q. The value of α is _______.
    Correct answer is '0.22'. Can you explain this answer?
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    At 298 K, the limiting molar conductivity of a weak monobasic acid is ...
    Y can be calculated using the equation:

    Molar conductivity = Limiting molar conductivity × Degree of dissociation

    Given that the molar conductivity of the acid is y × 10^2 S cm^2 mol^-1, we can write:

    y × 10^2 = 4 × 10^2 × Degree of dissociation

    Rearranging the equation, we find:

    Degree of dissociation = (y × 10^2) / (4 × 10^2)

    Upon 20 times dilution with water, the molar conductivity of the solution becomes 3y × 10^2 S cm^2 mol^-1. This means that the degree of dissociation remains the same upon dilution.

    Therefore, the value of y remains the same after dilution, and it is equal to the original value, which is 4.
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    Community Answer
    At 298 K, the limiting molar conductivity of a weak monobasic acid is ...

    On dilution, conductivity increases three times.

    Since temperature is constant, Ka will be constant.
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    At 298 K, the limiting molar conductivity of a weak monobasic acid is 4 x 102 S cm2 mol-1. At 298 K, for an aqueous solution of the acid, the degree of dissociation is and the molar conductivity is y x 102 S cm2 mol-1. At 298 K, upon 20 times dilution with water, the molar conductivity of the solution becomes 3y x 102 S cm2 mol-1.Q. The value of αis _______.Correct answer is '0.22'. Can you explain this answer?
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    At 298 K, the limiting molar conductivity of a weak monobasic acid is 4 x 102 S cm2 mol-1. At 298 K, for an aqueous solution of the acid, the degree of dissociation is and the molar conductivity is y x 102 S cm2 mol-1. At 298 K, upon 20 times dilution with water, the molar conductivity of the solution becomes 3y x 102 S cm2 mol-1.Q. The value of αis _______.Correct answer is '0.22'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about At 298 K, the limiting molar conductivity of a weak monobasic acid is 4 x 102 S cm2 mol-1. At 298 K, for an aqueous solution of the acid, the degree of dissociation is and the molar conductivity is y x 102 S cm2 mol-1. At 298 K, upon 20 times dilution with water, the molar conductivity of the solution becomes 3y x 102 S cm2 mol-1.Q. The value of αis _______.Correct answer is '0.22'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 298 K, the limiting molar conductivity of a weak monobasic acid is 4 x 102 S cm2 mol-1. At 298 K, for an aqueous solution of the acid, the degree of dissociation is and the molar conductivity is y x 102 S cm2 mol-1. At 298 K, upon 20 times dilution with water, the molar conductivity of the solution becomes 3y x 102 S cm2 mol-1.Q. The value of αis _______.Correct answer is '0.22'. Can you explain this answer?.
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