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At 15 degrees centigrade the percent of dissociation of a weak monobasic acid in its aqua solution with a concentration N/20 is 3.5 % the degree of dissociation of the acid at the temperature is?
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At 15 degrees centigrade the percent of dissociation of a weak monobas...
Degree of Dissociation of a Weak Monobasic Acid at 15°C

Given:
- Temperature: 15°C
- Concentration of aqua solution: N/20
- Percent of dissociation: 3.5%

To Find: Degree of dissociation of the acid at the temperature

Solution:
1. Calculate the dissociation constant (Ka) of the weak monobasic acid using the percent dissociation formula:
% dissociation = (Ka / [acid]) x 100
where [acid] is the initial concentration of the acid

Rearranging the formula:
Ka = (% dissociation x [acid]) / 100

Substituting the given values:
Ka = (3.5 x N/20) / 100
Ka = 0.007N

2. Calculate the degree of dissociation (α) of the acid using the dissociation constant:
Ka = [H+][A-] / [HA]
where [H+], [A-], and [HA] are the concentrations of hydrogen ions, conjugate base, and undissociated acid, respectively

Assuming the initial concentration of the acid to be x:
Ka = (αx)² / (1 - αx)

Substituting the value of Ka:
0.007N = (αx)² / (1 - αx)

Solving for α:
α = 0.07 / (x + 0.007N)

3. Substitute the given concentration N/20 for x and calculate the degree of dissociation:
α = 0.07 / (N/20 + 0.007N)
α = 0.065 or 6.5% (approx.)

Therefore, the degree of dissociation of the weak monobasic acid at 15°C is approximately 6.5%.
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At 15 degrees centigrade the percent of dissociation of a weak monobasic acid in its aqua solution with a concentration N/20 is 3.5 % the degree of dissociation of the acid at the temperature is?
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