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A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ present in 250 mL solution is x × 10−2 (consider complete dissolution of FeCl2). The amount of iron present in the sample is y% by weight.(Assume: KMnO4 reacts only with Fe2+ in the solution, Use: Molar mass of iron as 56 g mol−1)Q.The value of y is _______.Correct answer is '18.75'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ present in 250 mL solution is x × 10−2 (consider complete dissolution of FeCl2). The amount of iron present in the sample is y% by weight.(Assume: KMnO4 reacts only with Fe2+ in the solution, Use: Molar mass of iron as 56 g mol−1)Q.The value of y is _______.Correct answer is '18.75'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ present in 250 mL solution is x × 10−2 (consider complete dissolution of FeCl2). The amount of iron present in the sample is y% by weight.(Assume: KMnO4 reacts only with Fe2+ in the solution, Use: Molar mass of iron as 56 g mol−1)Q.The value of y is _______.Correct answer is '18.75'. Can you explain this answer?.

Solutions for A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ present in 250 mL solution is x × 10−2 (consider complete dissolution of FeCl2). The amount of iron present in the sample is y% by weight.(Assume: KMnO4 reacts only with Fe2+ in the solution, Use: Molar mass of iron as 56 g mol−1)Q.The value of y is _______.Correct answer is '18.75'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ present in 250 mL solution is x × 10−2 (consider complete dissolution of FeCl2). The amount of iron present in the sample is y% by weight.(Assume: KMnO4 reacts only with Fe2+ in the solution, Use: Molar mass of iron as 56 g mol−1)Q.The value of y is _______.Correct answer is '18.75'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ present in 250 mL solution is x × 10−2 (consider complete dissolution of FeCl2). The amount of iron present in the sample is y% by weight.(Assume: KMnO4 reacts only with Fe2+ in the solution, Use: Molar mass of iron as 56 g mol−1)Q.The value of y is _______.Correct answer is '18.75'. Can you explain this answer?, a detailed solution for A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ present in 250 mL solution is x × 10−2 (consider complete dissolution of FeCl2). The amount of iron present in the sample is y% by weight.(Assume: KMnO4 reacts only with Fe2+ in the solution, Use: Molar mass of iron as 56 g mol−1)Q.The value of y is _______.Correct answer is '18.75'. Can you explain this answer? has been provided alongside types of A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ present in 250 mL solution is x × 10−2 (consider complete dissolution of FeCl2). The amount of iron present in the sample is y% by weight.(Assume: KMnO4 reacts only with Fe2+ in the solution, Use: Molar mass of iron as 56 g mol−1)Q.The value of y is _______.Correct answer is '18.75'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ present in 250 mL solution is x × 10−2 (consider complete dissolution of FeCl2). The amount of iron present in the sample is y% by weight.(Assume: KMnO4 reacts only with Fe2+ in the solution, Use: Molar mass of iron as 56 g mol−1)Q.The value of y is _______.Correct answer is '18.75'. Can you explain this answer? tests, examples and also practice JEE tests.