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In a steam engine, the maximum steam pressure is 1.5 N/mm2 absolute and the back pressure is 0.514 N/mm2 absolute. The cylinder diameter is 0.3 m. What will be the diameter (in mm) of the screwed end of the piston rod when the allowable stress of mild steel is 45.0 N/mm2 in tension? (Answer up to one decimal place)
Correct answer is '44.4'. Can you explain this answer?
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In a steam engine, the maximum steam pressure is 1.5 N/mm2 absolute an...
Given parameters:
- Maximum steam pressure: 1.5 N/mm2
- Back pressure: 0.514 N/mm2
- Cylinder diameter: 0.3 m
- Allowable stress of mild steel in tension: 45.0 N/mm2
To find: Diameter of the screwed end of the piston rod
Assumptions:
- Steam engine operates on a single-acting cylinder
- Neglecting frictional losses
Formulae used:
- Force exerted by steam on the piston = (P1 - P2) x A
- Force exerted by steam on the piston = (π/4) x D2 x P1
- Force exerted by piston on the rod = Force exerted by steam on the piston
- Stress in the piston rod = Force exerted by piston on the rod / Area of the rod
- Area of the rod = (π/4) x d2
Solution:
1. Calculating the force exerted by steam on the piston:
- P1 = 1.5 N/mm2 (maximum steam pressure)
- P2 = 0.514 N/mm2 (back pressure)
- A = (π/4) x (0.3 m)2 = 0.0707 m2 (cylinder area)
- Force exerted by steam on the piston = (P1 - P2) x A = (1.5 - 0.514) x 0.0707 = 0.0702 MN
2. Calculating the stress in the piston rod:
- Stress in the piston rod = Force exerted by piston on the rod / Area of the rod
- Area of the rod = (π/4) x d2
- Stress in the piston rod = 45.0 N/mm2 (allowable stress)
- Force exerted by piston on the rod = 0.0702 MN (calculated in step 1)
- (π/4) x d2 = (0.0702 x 106) / 45.0
- d2 = (0.0702 x 106 x 4) / (45.0 x π)
- d = √(d2) = √((0.0702 x 106 x 4) / (45.0 x π)) = 44.4 mm (rounded to one decimal place)
Therefore, the diameter of the screwed end of the piston rod is 44.4 mm.
- Maximum steam pressure: 1.5 N/mm2
- Back pressure: 0.514 N/mm2
- Cylinder diameter: 0.3 m
- Allowable stress of mild steel in tension: 45.0 N/mm2
To find: Diameter of the screwed end of the piston rod
Assumptions:
- Steam engine operates on a single-acting cylinder
- Neglecting frictional losses
Formulae used:
- Force exerted by steam on the piston = (P1 - P2) x A
- Force exerted by steam on the piston = (π/4) x D2 x P1
- Force exerted by piston on the rod = Force exerted by steam on the piston
- Stress in the piston rod = Force exerted by piston on the rod / Area of the rod
- Area of the rod = (π/4) x d2
Solution:
1. Calculating the force exerted by steam on the piston:
- P1 = 1.5 N/mm2 (maximum steam pressure)
- P2 = 0.514 N/mm2 (back pressure)
- A = (π/4) x (0.3 m)2 = 0.0707 m2 (cylinder area)
- Force exerted by steam on the piston = (P1 - P2) x A = (1.5 - 0.514) x 0.0707 = 0.0702 MN
2. Calculating the stress in the piston rod:
- Stress in the piston rod = Force exerted by piston on the rod / Area of the rod
- Area of the rod = (π/4) x d2
- Stress in the piston rod = 45.0 N/mm2 (allowable stress)
- Force exerted by piston on the rod = 0.0702 MN (calculated in step 1)
- (π/4) x d2 = (0.0702 x 106) / 45.0
- d2 = (0.0702 x 106 x 4) / (45.0 x π)
- d = √(d2) = √((0.0702 x 106 x 4) / (45.0 x π)) = 44.4 mm (rounded to one decimal place)
Therefore, the diameter of the screwed end of the piston rod is 44.4 mm.
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In a steam engine, the maximum steam pressure is 1.5 N/mm2 absolute an...
The maximum tensile load on the piston,
This load is to be resisted by the core area of the screwed end of piston
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In a steam engine, the maximum steam pressure is 1.5 N/mm2 absolute and the back pressure is 0.514 N/mm2 absolute. The cylinder diameter is 0.3 m. What will be the diameter (in mm) of the screwed end of the piston rod when the allowable stress of mild steel is 45.0 N/mm2 in tension? (Answer up to one decimal place)Correct answer is '44.4'. Can you explain this answer?
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In a steam engine, the maximum steam pressure is 1.5 N/mm2 absolute and the back pressure is 0.514 N/mm2 absolute. The cylinder diameter is 0.3 m. What will be the diameter (in mm) of the screwed end of the piston rod when the allowable stress of mild steel is 45.0 N/mm2 in tension? (Answer up to one decimal place)Correct answer is '44.4'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a steam engine, the maximum steam pressure is 1.5 N/mm2 absolute and the back pressure is 0.514 N/mm2 absolute. The cylinder diameter is 0.3 m. What will be the diameter (in mm) of the screwed end of the piston rod when the allowable stress of mild steel is 45.0 N/mm2 in tension? (Answer up to one decimal place)Correct answer is '44.4'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a steam engine, the maximum steam pressure is 1.5 N/mm2 absolute and the back pressure is 0.514 N/mm2 absolute. The cylinder diameter is 0.3 m. What will be the diameter (in mm) of the screwed end of the piston rod when the allowable stress of mild steel is 45.0 N/mm2 in tension? (Answer up to one decimal place)Correct answer is '44.4'. Can you explain this answer?.
In a steam engine, the maximum steam pressure is 1.5 N/mm2 absolute and the back pressure is 0.514 N/mm2 absolute. The cylinder diameter is 0.3 m. What will be the diameter (in mm) of the screwed end of the piston rod when the allowable stress of mild steel is 45.0 N/mm2 in tension? (Answer up to one decimal place)Correct answer is '44.4'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a steam engine, the maximum steam pressure is 1.5 N/mm2 absolute and the back pressure is 0.514 N/mm2 absolute. The cylinder diameter is 0.3 m. What will be the diameter (in mm) of the screwed end of the piston rod when the allowable stress of mild steel is 45.0 N/mm2 in tension? (Answer up to one decimal place)Correct answer is '44.4'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a steam engine, the maximum steam pressure is 1.5 N/mm2 absolute and the back pressure is 0.514 N/mm2 absolute. The cylinder diameter is 0.3 m. What will be the diameter (in mm) of the screwed end of the piston rod when the allowable stress of mild steel is 45.0 N/mm2 in tension? (Answer up to one decimal place)Correct answer is '44.4'. Can you explain this answer?.
Solutions for In a steam engine, the maximum steam pressure is 1.5 N/mm2 absolute and the back pressure is 0.514 N/mm2 absolute. The cylinder diameter is 0.3 m. What will be the diameter (in mm) of the screwed end of the piston rod when the allowable stress of mild steel is 45.0 N/mm2 in tension? (Answer up to one decimal place)Correct answer is '44.4'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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