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The boiling point of water in a 0.1 molal silver nitrate solution (solution A) is x°C. To this solution A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y × 10-2°C.(Assume: Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.Use: Molal elevation constant (Ebullioscopic Constant), Kb= 0.5 K kg mol-1; Boiling point of pure water is 100°C.)Q. The value of xis ___.Correct answer is '100.10°C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The boiling point of water in a 0.1 molal silver nitrate solution (solution A) is x°C. To this solution A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y × 10-2°C.(Assume: Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.Use: Molal elevation constant (Ebullioscopic Constant), Kb= 0.5 K kg mol-1; Boiling point of pure water is 100°C.)Q. The value of xis ___.Correct answer is '100.10°C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The boiling point of water in a 0.1 molal silver nitrate solution (solution A) is x°C. To this solution A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y × 10-2°C.(Assume: Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.Use: Molal elevation constant (Ebullioscopic Constant), Kb= 0.5 K kg mol-1; Boiling point of pure water is 100°C.)Q. The value of xis ___.Correct answer is '100.10°C'. Can you explain this answer?.

Solutions for The boiling point of water in a 0.1 molal silver nitrate solution (solution A) is x°C. To this solution A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y × 10-2°C.(Assume: Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.Use: Molal elevation constant (Ebullioscopic Constant), Kb= 0.5 K kg mol-1; Boiling point of pure water is 100°C.)Q. The value of xis ___.Correct answer is '100.10°C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The boiling point of water in a 0.1 molal silver nitrate solution (solution A) is x°C. To this solution A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y × 10-2°C.(Assume: Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.Use: Molal elevation constant (Ebullioscopic Constant), Kb= 0.5 K kg mol-1; Boiling point of pure water is 100°C.)Q. The value of xis ___.Correct answer is '100.10°C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The boiling point of water in a 0.1 molal silver nitrate solution (solution A) is x°C. To this solution A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y × 10-2°C.(Assume: Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.Use: Molal elevation constant (Ebullioscopic Constant), Kb= 0.5 K kg mol-1; Boiling point of pure water is 100°C.)Q. The value of xis ___.Correct answer is '100.10°C'. Can you explain this answer?, a detailed solution for The boiling point of water in a 0.1 molal silver nitrate solution (solution A) is x°C. To this solution A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y × 10-2°C.(Assume: Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.Use: Molal elevation constant (Ebullioscopic Constant), Kb= 0.5 K kg mol-1; Boiling point of pure water is 100°C.)Q. The value of xis ___.Correct answer is '100.10°C'. Can you explain this answer? has been provided alongside types of The boiling point of water in a 0.1 molal silver nitrate solution (solution A) is x°C. To this solution A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y × 10-2°C.(Assume: Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.Use: Molal elevation constant (Ebullioscopic Constant), Kb= 0.5 K kg mol-1; Boiling point of pure water is 100°C.)Q. The value of xis ___.Correct answer is '100.10°C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The boiling point of water in a 0.1 molal silver nitrate solution (solution A) is x°C. To this solution A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y × 10-2°C.(Assume: Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.Use: Molal elevation constant (Ebullioscopic Constant), Kb= 0.5 K kg mol-1; Boiling point of pure water is 100°C.)Q. The value of xis ___.Correct answer is '100.10°C'. Can you explain this answer? tests, examples and also practice JEE tests.