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Consider the lines L1and L2defined by L1: x√2 + y - 1 = 0 and L2: x√2 - y + 1 = 0.For a fixed constantλ , let C be the locus of a point P such that the product of the distance of P from L1and the distance of P from L2is λ2. The line y = 2x + 1 meets C at two points R and S, where the distance between R and S is√270Let the perpendicular bisector of RS meet C at two distinct points R and S. Let D be the square of the distance between R and SQ. The value of Dis _____.Correct answer is '77.14'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Consider the lines L1and L2defined by L1: x√2 + y - 1 = 0 and L2: x√2 - y + 1 = 0.For a fixed constantλ , let C be the locus of a point P such that the product of the distance of P from L1and the distance of P from L2is λ2. The line y = 2x + 1 meets C at two points R and S, where the distance between R and S is√270Let the perpendicular bisector of RS meet C at two distinct points R and S. Let D be the square of the distance between R and SQ. The value of Dis _____.Correct answer is '77.14'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the lines L1and L2defined by L1: x√2 + y - 1 = 0 and L2: x√2 - y + 1 = 0.For a fixed constantλ , let C be the locus of a point P such that the product of the distance of P from L1and the distance of P from L2is λ2. The line y = 2x + 1 meets C at two points R and S, where the distance between R and S is√270Let the perpendicular bisector of RS meet C at two distinct points R and S. Let D be the square of the distance between R and SQ. The value of Dis _____.Correct answer is '77.14'. Can you explain this answer?.

Solutions for Consider the lines L1and L2defined by L1: x√2 + y - 1 = 0 and L2: x√2 - y + 1 = 0.For a fixed constantλ , let C be the locus of a point P such that the product of the distance of P from L1and the distance of P from L2is λ2. The line y = 2x + 1 meets C at two points R and S, where the distance between R and S is√270Let the perpendicular bisector of RS meet C at two distinct points R and S. Let D be the square of the distance between R and SQ. The value of Dis _____.Correct answer is '77.14'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Consider the lines L1and L2defined by L1: x√2 + y - 1 = 0 and L2: x√2 - y + 1 = 0.For a fixed constantλ , let C be the locus of a point P such that the product of the distance of P from L1and the distance of P from L2is λ2. The line y = 2x + 1 meets C at two points R and S, where the distance between R and S is√270Let the perpendicular bisector of RS meet C at two distinct points R and S. Let D be the square of the distance between R and SQ. The value of Dis _____.Correct answer is '77.14'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Consider the lines L1and L2defined by L1: x√2 + y - 1 = 0 and L2: x√2 - y + 1 = 0.For a fixed constantλ , let C be the locus of a point P such that the product of the distance of P from L1and the distance of P from L2is λ2. The line y = 2x + 1 meets C at two points R and S, where the distance between R and S is√270Let the perpendicular bisector of RS meet C at two distinct points R and S. Let D be the square of the distance between R and SQ. The value of Dis _____.Correct answer is '77.14'. Can you explain this answer?, a detailed solution for Consider the lines L1and L2defined by L1: x√2 + y - 1 = 0 and L2: x√2 - y + 1 = 0.For a fixed constantλ , let C be the locus of a point P such that the product of the distance of P from L1and the distance of P from L2is λ2. The line y = 2x + 1 meets C at two points R and S, where the distance between R and S is√270Let the perpendicular bisector of RS meet C at two distinct points R and S. Let D be the square of the distance between R and SQ. The value of Dis _____.Correct answer is '77.14'. Can you explain this answer? has been provided alongside types of Consider the lines L1and L2defined by L1: x√2 + y - 1 = 0 and L2: x√2 - y + 1 = 0.For a fixed constantλ , let C be the locus of a point P such that the product of the distance of P from L1and the distance of P from L2is λ2. The line y = 2x + 1 meets C at two points R and S, where the distance between R and S is√270Let the perpendicular bisector of RS meet C at two distinct points R and S. Let D be the square of the distance between R and SQ. The value of Dis _____.Correct answer is '77.14'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Consider the lines L1and L2defined by L1: x√2 + y - 1 = 0 and L2: x√2 - y + 1 = 0.For a fixed constantλ , let C be the locus of a point P such that the product of the distance of P from L1and the distance of P from L2is λ2. The line y = 2x + 1 meets C at two points R and S, where the distance between R and S is√270Let the perpendicular bisector of RS meet C at two distinct points R and S. Let D be the square of the distance between R and SQ. The value of Dis _____.Correct answer is '77.14'. Can you explain this answer? tests, examples and also practice JEE tests.