JEE Exam  >  JEE Questions  >  Moment of Inertia (M.I.) of four bodies havin... Start Learning for Free
Moment of Inertia (M.I.) of four bodies having same mass 'M' and radius '2R' are as follows:
l1 = M.I. of solid sphere about its diameter
l2 = M.I. of solid cylinder about its axis
I3 = M.I. of solid circular disc about its diameter
I4 = M.I. of thin circular ring about its diameter
If 2(I2 + I3) + I4 = x⋅I1, then the value of x will be _________.
    Correct answer is '5'. Can you explain this answer?
    Most Upvoted Answer
    Moment of Inertia (M.I.) of four bodies having same mass M and radius ...
    To solve this problem, we need to use the formulas for the moment of inertia of each of the four bodies.

    1. Moment of inertia of a solid sphere about its diameter (l1):
    l1 = (2/5) * M * R^2

    2. Moment of inertia of a solid cylinder about its axis (l2):
    l2 = (1/2) * M * R^2

    3. Moment of inertia of a solid circular disc about its diameter (I3):
    I3 = (1/4) * M * R^2

    4. Moment of inertia of a thin circular ring about its diameter (I4):
    I4 = M * R^2

    Now, let's substitute these values into the equation 2(I2 - I3) + I4 = x and simplify it.

    2(I2 - I3) + I4 = x
    2[(1/2) * M * R^2 - (1/4) * M * R^2] + M * R^2 = x
    2[(1/4) * M * R^2] + M * R^2 = x
    (1/2) * M * R^2 + M * R^2 = x
    (3/2) * M * R^2 = x

    Therefore, the value of x is (3/2) * M * R^2.
    Free Test
    Community Answer
    Moment of Inertia (M.I.) of four bodies having same mass M and radius ...

    x = 5
    Explore Courses for JEE exam
    Moment of Inertia (M.I.) of four bodies having same mass M and radius 2R are as follows:l1 = M.I. of solid sphere about its diameterl2 = M.I. of solid cylinder about its axisI3 = M.I. of solid circular disc about its diameterI4 = M.I. of thin circular ring about its diameterIf 2(I2 + I3) + I4 = x⋅I1, then the value of x will be _________.Correct answer is '5'. Can you explain this answer?
    Question Description
    Moment of Inertia (M.I.) of four bodies having same mass M and radius 2R are as follows:l1 = M.I. of solid sphere about its diameterl2 = M.I. of solid cylinder about its axisI3 = M.I. of solid circular disc about its diameterI4 = M.I. of thin circular ring about its diameterIf 2(I2 + I3) + I4 = x⋅I1, then the value of x will be _________.Correct answer is '5'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Moment of Inertia (M.I.) of four bodies having same mass M and radius 2R are as follows:l1 = M.I. of solid sphere about its diameterl2 = M.I. of solid cylinder about its axisI3 = M.I. of solid circular disc about its diameterI4 = M.I. of thin circular ring about its diameterIf 2(I2 + I3) + I4 = x⋅I1, then the value of x will be _________.Correct answer is '5'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Moment of Inertia (M.I.) of four bodies having same mass M and radius 2R are as follows:l1 = M.I. of solid sphere about its diameterl2 = M.I. of solid cylinder about its axisI3 = M.I. of solid circular disc about its diameterI4 = M.I. of thin circular ring about its diameterIf 2(I2 + I3) + I4 = x⋅I1, then the value of x will be _________.Correct answer is '5'. Can you explain this answer?.
    Solutions for Moment of Inertia (M.I.) of four bodies having same mass M and radius 2R are as follows:l1 = M.I. of solid sphere about its diameterl2 = M.I. of solid cylinder about its axisI3 = M.I. of solid circular disc about its diameterI4 = M.I. of thin circular ring about its diameterIf 2(I2 + I3) + I4 = x⋅I1, then the value of x will be _________.Correct answer is '5'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
    Here you can find the meaning of Moment of Inertia (M.I.) of four bodies having same mass M and radius 2R are as follows:l1 = M.I. of solid sphere about its diameterl2 = M.I. of solid cylinder about its axisI3 = M.I. of solid circular disc about its diameterI4 = M.I. of thin circular ring about its diameterIf 2(I2 + I3) + I4 = x⋅I1, then the value of x will be _________.Correct answer is '5'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Moment of Inertia (M.I.) of four bodies having same mass M and radius 2R are as follows:l1 = M.I. of solid sphere about its diameterl2 = M.I. of solid cylinder about its axisI3 = M.I. of solid circular disc about its diameterI4 = M.I. of thin circular ring about its diameterIf 2(I2 + I3) + I4 = x⋅I1, then the value of x will be _________.Correct answer is '5'. Can you explain this answer?, a detailed solution for Moment of Inertia (M.I.) of four bodies having same mass M and radius 2R are as follows:l1 = M.I. of solid sphere about its diameterl2 = M.I. of solid cylinder about its axisI3 = M.I. of solid circular disc about its diameterI4 = M.I. of thin circular ring about its diameterIf 2(I2 + I3) + I4 = x⋅I1, then the value of x will be _________.Correct answer is '5'. Can you explain this answer? has been provided alongside types of Moment of Inertia (M.I.) of four bodies having same mass M and radius 2R are as follows:l1 = M.I. of solid sphere about its diameterl2 = M.I. of solid cylinder about its axisI3 = M.I. of solid circular disc about its diameterI4 = M.I. of thin circular ring about its diameterIf 2(I2 + I3) + I4 = x⋅I1, then the value of x will be _________.Correct answer is '5'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Moment of Inertia (M.I.) of four bodies having same mass M and radius 2R are as follows:l1 = M.I. of solid sphere about its diameterl2 = M.I. of solid cylinder about its axisI3 = M.I. of solid circular disc about its diameterI4 = M.I. of thin circular ring about its diameterIf 2(I2 + I3) + I4 = x⋅I1, then the value of x will be _________.Correct answer is '5'. Can you explain this answer? tests, examples and also practice JEE tests.
    Explore Courses for JEE exam

    Top Courses for JEE

    Explore Courses
    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev