JEE Exam > JEE Questions > Q2. A 24 kW, 250 V, 1600 RPM separately excit...
Start Learning for Free
Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. The
machine is first run at rated speed and the field current is adjusted to give an open circuit voltage of
260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motor
is found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Field
flux remains unaltered.?
machine is first run at rated speed and the field current is adjusted to give an open circuit voltage of
260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motor
is found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Field
flux remains unaltered.?
Most Upvoted Answer
Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armat...
Given:
Power output (P) = 24 kW
Terminal voltage (Vt) = 250 V
Speed (N) = 1600 RPM
Armature resistance (Ra) = 0.1 Ω
Open circuit voltage (Voc) = 260 V
Loaded speed (Nl) = 1500 RPM
Field flux remains unaltered
Calculations:
Back EMF (Eb) = Voc - Ia*Ra
where Ia is the armature current
At open circuit, Ia = 0, hence Eb = Voc
At rated load, P = Vt*Ia
Therefore, Ia = P/Vt
Speed of the motor is given by the relation: N = (Vt - Eb)/(2.5 * 10^-2 * Eb)
where 2.5 * 10^-2 is a constant
Substituting the given values, we get:
1600 = (260 - Eb)/(2.5 * 10^-2 * Eb)
On solving the above equation, we get:
Eb = 227.27 V
At rated load, Ia = P/Vt = 24/250 = 0.096 A
Now, Vt = Eb + Ia*Ra
Substituting the given values, we get:
Vt = 227.27 + 0.096 * 0.1 = 227.27 + 0.0096 = 227.28 V
Answer:
The terminal voltage of the generator under the given conditions is 227.28 V. When the generator is loaded to deliver its rated current, the speed of the driving motor reduces to 1500 RPM. This is because the armature current increases when the generator is loaded, which results in an increase in the armature reaction and a decrease in the generated voltage. As a result, the speed of the driving motor reduces to maintain a balance between the mechanical power input and the electrical power output of the generator.
Power output (P) = 24 kW
Terminal voltage (Vt) = 250 V
Speed (N) = 1600 RPM
Armature resistance (Ra) = 0.1 Ω
Open circuit voltage (Voc) = 260 V
Loaded speed (Nl) = 1500 RPM
Field flux remains unaltered
Calculations:
Back EMF (Eb) = Voc - Ia*Ra
where Ia is the armature current
At open circuit, Ia = 0, hence Eb = Voc
At rated load, P = Vt*Ia
Therefore, Ia = P/Vt
Speed of the motor is given by the relation: N = (Vt - Eb)/(2.5 * 10^-2 * Eb)
where 2.5 * 10^-2 is a constant
Substituting the given values, we get:
1600 = (260 - Eb)/(2.5 * 10^-2 * Eb)
On solving the above equation, we get:
Eb = 227.27 V
At rated load, Ia = P/Vt = 24/250 = 0.096 A
Now, Vt = Eb + Ia*Ra
Substituting the given values, we get:
Vt = 227.27 + 0.096 * 0.1 = 227.27 + 0.0096 = 227.28 V
Answer:
The terminal voltage of the generator under the given conditions is 227.28 V. When the generator is loaded to deliver its rated current, the speed of the driving motor reduces to 1500 RPM. This is because the armature current increases when the generator is loaded, which results in an increase in the armature reaction and a decrease in the generated voltage. As a result, the speed of the driving motor reduces to maintain a balance between the mechanical power input and the electrical power output of the generator.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. Themachine is first run at rated speed and the field current is adjusted to give an open circuit voltage of260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motoris found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Fieldflux remains unaltered.?
Question Description
Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. Themachine is first run at rated speed and the field current is adjusted to give an open circuit voltage of260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motoris found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Fieldflux remains unaltered.? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. Themachine is first run at rated speed and the field current is adjusted to give an open circuit voltage of260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motoris found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Fieldflux remains unaltered.? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. Themachine is first run at rated speed and the field current is adjusted to give an open circuit voltage of260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motoris found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Fieldflux remains unaltered.?.
Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. Themachine is first run at rated speed and the field current is adjusted to give an open circuit voltage of260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motoris found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Fieldflux remains unaltered.? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. Themachine is first run at rated speed and the field current is adjusted to give an open circuit voltage of260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motoris found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Fieldflux remains unaltered.? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. Themachine is first run at rated speed and the field current is adjusted to give an open circuit voltage of260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motoris found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Fieldflux remains unaltered.?.
Solutions for Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. Themachine is first run at rated speed and the field current is adjusted to give an open circuit voltage of260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motoris found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Fieldflux remains unaltered.? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. Themachine is first run at rated speed and the field current is adjusted to give an open circuit voltage of260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motoris found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Fieldflux remains unaltered.? defined & explained in the simplest way possible. Besides giving the explanation of
Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. Themachine is first run at rated speed and the field current is adjusted to give an open circuit voltage of260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motoris found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Fieldflux remains unaltered.?, a detailed solution for Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. Themachine is first run at rated speed and the field current is adjusted to give an open circuit voltage of260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motoris found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Fieldflux remains unaltered.? has been provided alongside types of Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. Themachine is first run at rated speed and the field current is adjusted to give an open circuit voltage of260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motoris found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Fieldflux remains unaltered.? theory, EduRev gives you an
ample number of questions to practice Q2. A 24 kW, 250 V, 1600 RPM separately excited dc generator has armature resistance of 0.1 Ω. Themachine is first run at rated speed and the field current is adjusted to give an open circuit voltage of260 V. Now, when the generator is loaded to deliver its rated current, the speed of the driving motoris found to be 1500 RPM. Compute the terminal voltage of the generator under these conditions. Fieldflux remains unaltered.? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup