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A 500V d.c shunt motor has armature and field resistances of 0.5Ω and 200Ω respectively. When loaded and taking a total input of 25kW, it runs at 400rpm. Find the speed at which it must be driven as a shunt generator to supply a power output of 25kW at a terminal voltage of 500V.?
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A 500V d.c shunt motor has armature and field resistances of 0.5Ω and ...
Given:

Voltage (V) = 500V

Armature Resistance (Ra) = 0.5Ω

Field Resistance (Rf) = 200Ω

Input Power (Pin) = 25kW

Speed (N) = 400rpm


To Find:

Speed as a Shunt Generator (Ns)


Solution:

Step 1: Calculate the armature current (Ia) using the formula:

Ia = Pin/V

Ia = 25,000/500

Ia = 50A


Step 2: Calculate the back emf (Eb) using the formula:

Eb = V - Ia*Ra

Eb = 500 - (50*0.5)

Eb = 475V


Step 3: Calculate the flux (Φ) using the formula:

Φ = Eb/Rf

Φ = 475/200

Φ = 2.375Wb


Step 4: Calculate the speed as a shunt generator (Ns) using the formula:

Ns = (V + Ia*Ra)/Φ

Ns = (500 + (50*0.5))/2.375

Ns = 213.16rpm


Explanation:

A shunt motor is a motor that is connected in parallel with a resistance. It is used to supply power to a load. The shunt motor works on the principle of electromagnetic induction. When an electric current flows through a conductor, it creates a magnetic field. The magnetic field interacts with the magnetic field of the stator, and the rotor starts to rotate. The speed of the motor depends on the voltage, the armature resistance, and the field resistance.

When the shunt motor is loaded and taking a total input of 25kW, it runs at 400rpm. To find the speed as a shunt generator, the armature current, back emf, and flux are calculated using the given formulas. The speed as a shunt generator is then calculated using the formula Ns = (V + Ia*Ra)/Φ.

Conclusion:

The speed of the shunt motor as a shunt generator to supply a power output of 25kW at a terminal voltage of 500V is 213.16rpm.
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A 500V d.c shunt motor has armature and field resistances of 0.5Ω and 200Ω respectively. When loaded and taking a total input of 25kW, it runs at 400rpm. Find the speed at which it must be driven as a shunt generator to supply a power output of 25kW at a terminal voltage of 500V.?
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A 500V d.c shunt motor has armature and field resistances of 0.5Ω and 200Ω respectively. When loaded and taking a total input of 25kW, it runs at 400rpm. Find the speed at which it must be driven as a shunt generator to supply a power output of 25kW at a terminal voltage of 500V.? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 500V d.c shunt motor has armature and field resistances of 0.5Ω and 200Ω respectively. When loaded and taking a total input of 25kW, it runs at 400rpm. Find the speed at which it must be driven as a shunt generator to supply a power output of 25kW at a terminal voltage of 500V.? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 500V d.c shunt motor has armature and field resistances of 0.5Ω and 200Ω respectively. When loaded and taking a total input of 25kW, it runs at 400rpm. Find the speed at which it must be driven as a shunt generator to supply a power output of 25kW at a terminal voltage of 500V.?.
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