All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
JEE Exam  >  JEE Questions  >  Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the... Start Learning for Free
Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the number of molecules with non-zero net dipole moment is _________.
    Correct answer is '3'. Can you explain this answer?
    Clear all your JEE doubts with EduRev
    Most Upvoted Answer
    Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the number of molecules with...
    Number of Molecules with Non-zero Net Dipole Moment

    Brief Explanation:
    The net dipole moment of a molecule is the vector sum of all the individual bond dipole moments in the molecule. A molecule will have a non-zero net dipole moment if its bond dipole moments do not cancel out. In other words, if the molecule is asymmetrical or has polar bonds, it will have a non-zero net dipole moment.

    Analysis:
    Let's analyze each molecule given and determine if it has a non-zero net dipole moment:

    1. BeF2 (Beryllium Fluoride):
    - BeF2 is a linear molecule with a central beryllium atom and two fluorine atoms.
    - The electronegativity difference between Be and F is small, resulting in polar bonds.
    - However, the molecule is symmetrical, and the bond dipole moments cancel out.
    - Therefore, BeF2 has a zero net dipole moment.

    2. BF3 (Boron Trifluoride):
    - BF3 is a trigonal planar molecule with a central boron atom and three fluorine atoms.
    - The electronegativity difference between B and F is significant, resulting in polar bonds.
    - The molecule is also asymmetrical, with the fluorine atoms arranged in a trigonal planar geometry.
    - The bond dipole moments do not cancel out, leading to a non-zero net dipole moment.
    - Therefore, BF3 has a non-zero net dipole moment.

    3. H2O (Water):
    - H2O is a bent molecule with a central oxygen atom and two hydrogen atoms.
    - The electronegativity difference between O and H is significant, resulting in polar bonds.
    - The molecule is also asymmetrical, with the hydrogen atoms arranged in a bent geometry.
    - The bond dipole moments do not cancel out, leading to a non-zero net dipole moment.
    - Therefore, H2O has a non-zero net dipole moment.

    4. NH3 (Ammonia):
    - NH3 is a pyramidal molecule with a central nitrogen atom and three hydrogen atoms.
    - The electronegativity difference between N and H is significant, resulting in polar bonds.
    - The molecule is also asymmetrical, with the hydrogen atoms arranged in a pyramidal geometry.
    - The bond dipole moments do not cancel out, leading to a non-zero net dipole moment.
    - Therefore, NH3 has a non-zero net dipole moment.

    5. CCl4 (Carbon Tetrachloride):
    - CCl4 is a tetrahedral molecule with a central carbon atom and four chlorine atoms.
    - The electronegativity difference between C and Cl is significant, resulting in polar bonds.
    - However, the molecule is symmetrical, and the bond dipole moments cancel out.
    - Therefore, CCl4 has a zero net dipole moment.

    6. HCl (Hydrogen Chloride):
    - HCl is a linear molecule with a central hydrogen atom and a chlorine atom.
    - The electronegativity difference between H and Cl is significant, resulting in a polar bond.
    - The molecule is asymmetrical due to the lone pair on chlorine, causing a bent shape.
    - The bond dipole moment does
    Free Test
    FREE
    Start Free Test
    		Start Free Test
    Community Answer
    Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the number of molecules with...
    Explore Courses for JEE exam

    Similar JEE Doubts

    The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

    The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

    The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

    Top Courses for JEEView all

    Top Courses for JEE

    Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the number of molecules with non-zero net dipole moment is _________.Correct answer is '3'. Can you explain this answer?
    Question Description
    Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the number of molecules with non-zero net dipole moment is _________.Correct answer is '3'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the number of molecules with non-zero net dipole moment is _________.Correct answer is '3'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the number of molecules with non-zero net dipole moment is _________.Correct answer is '3'. Can you explain this answer?.
    Solutions for Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the number of molecules with non-zero net dipole moment is _________.Correct answer is '3'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
    Here you can find the meaning of Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the number of molecules with non-zero net dipole moment is _________.Correct answer is '3'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the number of molecules with non-zero net dipole moment is _________.Correct answer is '3'. Can you explain this answer?, a detailed solution for Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the number of molecules with non-zero net dipole moment is _________.Correct answer is '3'. Can you explain this answer? has been provided alongside types of Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the number of molecules with non-zero net dipole moment is _________.Correct answer is '3'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Amongst BeF2, BF3, H2O, NH3 CCl4 and HCl, the number of molecules with non-zero net dipole moment is _________.Correct answer is '3'. Can you explain this answer? tests, examples and also practice JEE tests.
    Explore Courses for JEE exam

    Top Courses for JEE

    Explore Courses
    SaveJoin the Discussion on the App for FREE
    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev
    Get App
    © EduRev
    Education Revolution
    Signup to see your scores go up within 7 days!
    Access 1000+ FREE Docs, Videos and Tests
    Takes less than 10 seconds to signup