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In a network two hosts, A and B are connected by an intermediate router R. Host A is connected to R through Link 1, and Host B is connected to R though Link 2. Each Link is 500 meters long and has a bandwidth of 1 Gbps. Queuing delay of R is 10 microseconds and the propagation speed 2.5 × 105 km/s. The processing delay is negligible. What is the total transfer delay of 2 KB packet from A to B in microseconds?
  • a)
    35.56
  • b)
    40.39
  • c)
    46.768
  • d)
    68.29
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In a network two hosts, A and B are connected by an intermediate route...
Microseconds/meter.

To calculate the end-to-end delay between Host A and Host B, we need to consider several components:

1. Transmission delay: This is the time it takes to transmit the entire packet from the sender to the receiver. It can be calculated using the formula: Transmission delay = Packet size / Link bandwidth. In this case, the packet size is not given, so we cannot calculate the transmission delay.

2. Propagation delay: This is the time it takes for a bit to travel from the sender to the receiver. It can be calculated using the formula: Propagation delay = Distance / Propagation speed. In this case, the distance is 500 meters and the propagation speed is given as 2.5 microseconds/meter. Therefore, the propagation delay is: Propagation delay = 500 / 2.5 = 200 microseconds.

3. Queuing delay: This is the time it takes for a packet to wait in the queue at the router before it can be transmitted. It is given as 10 microseconds.

4. Processing delay: This is the time it takes for the router to process the packet before it can be transmitted. It is not given in the question, so we cannot calculate it.

Therefore, the end-to-end delay between Host A and Host B can be calculated as the sum of the propagation delay and the queuing delay: End-to-end delay = Propagation delay + Queuing delay = 200 + 10 = 210 microseconds.
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Community Answer
In a network two hosts, A and B are connected by an intermediate route...
Given,
Packet Size = 2 KB = 2
11
bytes = 2
14
bits
Bandwidth = 1 Gbps = 10
9
bps
Lenght of link 1= Lenght of link 2 = 500 m
Propagation speed = 2.5 × 10
5
km/s = 2.5 × 10
8
m/s
Queuing delay at R = 10 microseconds
Diagram:
As we know,
Total transfer delay = transmission delay from A to link 1+ propogation delay from A to R+ queuing delay at R+ transmission delay from R to link 2+ propagation delay from R to B
Now,
T
trans
  (from A to link 1)
 = T
trans
  (from R to link 2)
= 2
14
÷ 10
9
bps
= 16.384 microseconds
T
prop
 (from A to R)
= T
prop
 (form R to B)
= (500 m) ÷ (2.5 × 10
8
m/s)
= 2 microseconds
Total transfer delay = 16.384+0.2+10+16.384+2
= 46.768 microseconds
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In a network two hosts, A and B are connected by an intermediate router R. Host A is connected to R through Link 1, and Host B is connected to R though Link 2. Each Link is 500 meters long and has a bandwidth of 1 Gbps. Queuing delay of R is 10 microseconds and the propagation speed 2.5 × 105 km/s. The processing delay is negligible. What is the total transfer delay of 2 KB packet from A to B in microseconds?a)35.56b)40.39c)46.768d)68.29Correct answer is option 'C'. Can you explain this answer?
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