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The bit sequence 0010 is serially entered (right-most bit first) into a 4-bit parallel out shift register that is initially clear. What is the Q output after two clock pulses?
Correct answer is '1000'. Can you explain this answer?
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The bit sequence 0010 is serially entered (right-most bit first) into ...
Problem: Find the Q output after two clock pulses when the bit sequence 0010 is serially entered (right-most bit first) into a 4-bit parallel out shift register that is initially clear.
Solution:
To solve this problem, we need to understand the working of a shift register first. A shift register is a sequential circuit that stores and shifts data bits in a serial manner. In this problem, we have a 4-bit parallel out shift register, which means that it has four output pins Q0, Q1, Q2, and Q3, and it can shift four bits serially.
Initially, the shift register is clear, which means that all the output pins Q0, Q1, Q2, and Q3 are set to 0. The bit sequence 0010 is serially entered into the shift register in a right-to-left manner, which means that the rightmost bit 0 is entered first, followed by the next bit 1, and so on.
After the first clock pulse, the bit sequence shifts by one position to the left, and the rightmost bit 0 enters the shift register. As a result, the output pin Q0 becomes 0, Q1 becomes 0, Q2 becomes 1, and Q3 becomes 0.
After the second clock pulse, the bit sequence again shifts by one position to the left, and the rightmost bit 1 enters the shift register. As a result, the output pin Q0 becomes 0, Q1 becomes 0, Q2 becomes 0, and Q3 becomes 1.
Therefore, the Q output after two clock pulses is 1000.
Final Answer: The Q output after two clock pulses is 1000.
Solution:
To solve this problem, we need to understand the working of a shift register first. A shift register is a sequential circuit that stores and shifts data bits in a serial manner. In this problem, we have a 4-bit parallel out shift register, which means that it has four output pins Q0, Q1, Q2, and Q3, and it can shift four bits serially.
Initially, the shift register is clear, which means that all the output pins Q0, Q1, Q2, and Q3 are set to 0. The bit sequence 0010 is serially entered into the shift register in a right-to-left manner, which means that the rightmost bit 0 is entered first, followed by the next bit 1, and so on.
After the first clock pulse, the bit sequence shifts by one position to the left, and the rightmost bit 0 enters the shift register. As a result, the output pin Q0 becomes 0, Q1 becomes 0, Q2 becomes 1, and Q3 becomes 0.
After the second clock pulse, the bit sequence again shifts by one position to the left, and the rightmost bit 1 enters the shift register. As a result, the output pin Q0 becomes 0, Q1 becomes 0, Q2 becomes 0, and Q3 becomes 1.
Therefore, the Q output after two clock pulses is 1000.
Final Answer: The Q output after two clock pulses is 1000.
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The bit sequence 0010 is serially entered (right-most bit first) into ...
The operation of 4-bit parallel out shift register is as follows.
Let's assume that all the flip-flops have just been RESET and that all the outputs are at logic level 0, i.e. no parallel data output.
If the data input pin is connected to a logic ''1'', then on the first clock pulse, the output will be set HIGH to logic 1 with all the other outputs still remaining LOW at logic 0. Assume that the DATA input pin has returned LOW again to logic 0 giving us one data pulse or 0-1-0. The second clock pulse will change the output to logic 0 and the output is HIGH to logic 1 as its input has the logic 1 level on it from Q. The logic 1 has now moved or been shifted one place along the register to the right as it is now at Q. The output Q after two clock pulses is then 1000.
Let's assume that all the flip-flops have just been RESET and that all the outputs are at logic level 0, i.e. no parallel data output.
If the data input pin is connected to a logic ''1'', then on the first clock pulse, the output will be set HIGH to logic 1 with all the other outputs still remaining LOW at logic 0. Assume that the DATA input pin has returned LOW again to logic 0 giving us one data pulse or 0-1-0. The second clock pulse will change the output to logic 0 and the output is HIGH to logic 1 as its input has the logic 1 level on it from Q. The logic 1 has now moved or been shifted one place along the register to the right as it is now at Q. The output Q after two clock pulses is then 1000.
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The bit sequence 0010 is serially entered (right-most bit first) into a 4-bit parallel out shift register that is initially clear. What is the Q output after two clock pulses?Correct answer is '1000'. Can you explain this answer?
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