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The average of 5 numbers is 8. If the sum of the first two numbers is 14 and the sum of the last two numbers is 16 then find the middle number?
  • a)
    10
  • b)
    15
  • c)
    12
  • d)
    None of the above
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
The average of 5 numbers is 8. If the sum of the first two numbers is ...
To find the middle number, let's assume the five numbers as a, b, c, d, and e.

Given:
Average of 5 numbers = 8
Sum of the first two numbers (a + b) = 14
Sum of the last two numbers (d + e) = 16

We need to find the middle number, which is represented by c.

Calculating the sum of all five numbers:
(a + b + c + d + e)/5 = 8
(a + b + c + d + e) = 8 * 5
(a + b + c + d + e) = 40

From the given information, we have two more sums:
(a + b) = 14
(d + e) = 16

Using these three equations, we can find the values of (a + b) and (d + e) in terms of c:
(a + b + c + d + e) = 40
(14 + c + 16) = 40
(c + 30) = 40
c = 40 - 30
c = 10

Therefore, the middle number is 10.

Hence, the correct answer is option A) 10.
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Community Answer
The average of 5 numbers is 8. If the sum of the first two numbers is ...
The sum of the first two numbers is 14 and the last two numbers is 16.
The sum of all five numbers is = 5 x 8 = 40.
So, the remaining middle number = 40 -(14+16)
40-30 = 10.
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Directions:Read the information carefully to answer the question that follows.Dr. Ravi Patel teaches financial markets course at Indian Management Institute, which is being taught in two parts - one part in first trimester and the other part in second trimester. Initially, the professor divides the students randomly in five classes in first trimester and based on the performance of students in first trimester, he further divides the students of each class into two parts as below average and above average performers. It is observed that in each class, the ratio of below average and above average performers is at least 13/10.Initially, the classes were named as classes P, Q, R, S and T and after further division, the classes were renamed as classes 1, 2, 3, 4 ,....,10 and the classes in trimester 2 are named randomly i.e. it is not necessary that two parts of class A are numbered one after the other.It is also given that 1/5 of total students in first trimester were in class R, 23% of total students were in class Q and 17% of total students were in class T. The ratio of students in classes P and S was 11 : 9. In the second trimester, there were 20 students in class 1. The number of students in classes 3, 10 and 9 were twice, thrice and four times the number of students in class 1. The number of students in classes 4 and 5 are in ratio 1 : 3. The number of students in class 2 were 5 more than the number of students in class 9. The number of students in class 8 was 40% more than the number of students in class 4. The number of students in classes 6 and 7 is 50 and 30 and the total number of students in classes 4, 5 and 8 is 125% more than the number of students in class 10. Each student in first trimester was classified as either below average or above average performer.Q.What was the minimum difference between number of students who performed below average and number of students who performed above average in any class?

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The average of 5 numbers is 8. If the sum of the first two numbers is 14 and the sum of the last two numbers is 16 then find the middle number?a)10b)15c)12d)None of the aboveCorrect answer is option 'A'. Can you explain this answer?
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