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An equation 5005x 4 −bx 3 +cx 2 −dx+3774=0 has roots  α,  β, γ and δ  and such that each of the roots is in the form of p/q ​ where p and q are prime numbers. How many unordered quadruplets of roots α, β, γ, and δ are possible ?
  • a)
    32
  • b)
    24
  • c)
    16
  • d)
    12
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
An equation 5005x 4 −bx 3 +cx 2 −dx+3774=0 has roots &alph...
We have 5005 = 5 x 7 x 11 x 13 and 3774 = 2 x 3 x 17 x 37
The product of roots for the given polynomial is given by = 
Since, all the roots are of the for p/q where p,q ≠ 1 and both are prime.
∴ the roots should be such that the numerator must be one among 2, 3, 17 or 37 and the denominator must be one among 5, 7, 11 or 13.
Also, as each of the numbers is prime, so they will always be co-prime to each other.
For  '2' as numerator we can select one of the denominators in 4 ways.
For  '3' as numerator we can select one out of the remaining three denominators in 3 ways.
Similarly, For '17' as numerator we can select one out of the remaining two denominators in 2 ways.
And lastly for '37' as numerator we can select one out of the remaining one denominator in 1 way.
As all the selections are mutually dependent, so we have the total number of possible quadruplets as = 4 x 3 x 2 x 1 = 24
Hence, option B is the correct choice.
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An equation 5005x 4 −bx 3 +cx 2 −dx+3774=0 has roots α, β, γ and δ and such that each of the roots is in the form of p/q where p and q are prime numbers. How many unordered quadruplets of roots α, β, γ, and δ are possible ?a)32b)24c)16d)12Correct answer is option 'B'. Can you explain this answer?
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