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The volume of 0.0168 moles of O2 obtained by decomposition of kclo3 and collected by displacement of water is 428ml at a pressure of 754 mm Hg at 25degree centigrade the pressure of water vapour at 25 degree centigrade is?
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The volume of 0.0168 moles of O2 obtained by decomposition of kclo3 an...
2KClO3 --> 2KCl + 3O2
v = 0.428L = O2 + H2O vapor
well, you coud just look it up as it is a constant.but...
moles gas = pv/(rt)
n = 0.992atm x 0.428L / (0.0821L-atm/mole-K x 298K) = 0.0174moles gas (O2 + H2O)
mole fraction water vapor = (0.0174 - 0.0168) / 0.0174 = 0.0319

partial pressure H2O = 0.0319 x 0.992atm = 0.0317atm = 24.08mmHg
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The volume of 0.0168 moles of O2 obtained by decomposition of kclo3 and collected by displacement of water is 428ml at a pressure of 754 mm Hg at 25degree centigrade the pressure of water vapour at 25 degree centigrade is?
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