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If [Cu(H2O)4]2+ absorbs a light of wavelength 600 nm for d-d transition, then the value of octahedral crystal field splitting energy for [Cu(H2O)6]2+ will be ________ × 10-21 J. (Nearest Integer)
(Given: h = 6.63 × 10-34 Js and c = 3.08 × 108 ms-1)
    Correct answer is '766'. Can you explain this answer?
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    If [Cu(H2O)4]2+absorbs a light of wavelength 600 nm for d-d transition...
    The wavelength of light absorbed for d-d transition in [Cu(H2O)4]2 is related to the energy of the transition by the equation:

    ΔE = hc/λ

    where ΔE is the energy of the transition, h is Planck's constant, c is the speed of light, and λ is the wavelength of the absorbed light.

    Substituting the given values, we get:

    ΔE = (6.626 x 10^-34 J s)(3.00 x 10^8 m/s)/(600 x 10^-9 m) = 3.31 x 10^-19 J

    The energy of the transition is equal to the difference in energy between the two sets of d orbitals in the complex, which is given by the octahedral crystal field splitting energy (Δo).

    ΔE = 10Dq

    where Dq is the octahedral crystal field splitting energy.

    Solving for Dq, we get:

    Dq = ΔE/10 = (3.31 x 10^-19 J)/10 = 3.31 x 10^-20 J

    Now, for [Cu(H2O)6]2, the ligand field is stronger and hence the octahedral crystal field splitting energy will be greater than that for [Cu(H2O)4]2.

    Therefore, we can assume that the value of octahedral crystal field splitting energy for [Cu(H2O)6]2 will be greater than 3.31 x 10^-20 J. However, we cannot determine its exact value without additional information.
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    Community Answer
    If [Cu(H2O)4]2+absorbs a light of wavelength 600 nm for d-d transition...

    = 0.034034 × 10-17
    = 340.34 × 10-21 J

    = 9/4 × 340.34 × 10-21
    = 765.765 × 10-21 J
    ≈ 766 × 10-21 J
    Answer = 766
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    Crystal field theory views the bonding in complexes as arising from electrostatic interaction and considers the effect of the ligand charges on the energies of the metal ion d-orbitals.In this theory, a ligand lone pair is modelled as a point negative charge that repels electrons in the d-orbitals of the central metal ion. The theory concentrated on the resulting splitting of the d-orbitals in two groups with different energies and used that splitting to rationalize and correlate the optical spectra, thermodynamic stability, and magnetic properties of complexes. This energy splitting between the two sets of dorbitals is called the crystal field splitting D.In general, the crystal field splitting energy D corresponds to wavelength of light in visible region of the spectrum, and colours of the complexes can therefore be attributed to electronic transition between the lower-and higher energy sets of d-orbitals.In general, the colour that the we see is complementry to the colour absorbed.Different metal ion have different values of D, which explains why their complexes with the same ligand have different colour.Similarly, the crystal field splitting also depends on the nature of ligands and as the ligand for the same metal varies from H2O to NH3 to ethylenediamine, D for complexes increases. Accordingly, the electronic transition shifts to higher energy (shorter wavelength) as the ligand varies from H2O to NH3 to en, thus accounting for the variation in colour.Crystal field theory accounts for the magnetic properties of complexes in terms of the relative values of and the spin pairing energy P. Small values favour high spin complexes, and large Dvalues favour low spin complexes.The [Ti(NCS)6]3- ion exhibits a single absorption band at 544 nm. W hat will be the crystal field splitting energy (KJ mol-1) of the complex ? (h = 6.626 x 10-34 J.s ; C = 3.0 x 108 m/s; NA = 6.02 x 1023 ions/mole.

    Crystal field theory views the bonding in complexes as arising from electrostatic interaction and considers the effect of the ligand charges on the energies of the metal ion d-orbitals.In this theory, a ligand lone pair is modelled as a point negative charge that repels electrons in the d-orbitals of the central metal ion. The theory concentrated on the resulting splitting of the d-orbitals in two groups with different energies and used that splitting to rationalize and correlate the optical spectra, thermodynamic stability, and magnetic properties of complexes. This energy splitting between the two sets of dorbitals is called the crystal field splitting D.In general, the crystal field splitting energy D corresponds to wavelength of light in visible region of the spectrum, and colours of the complexes can therefore be attributed to electronic transition between the lower-and higher energy sets of d-orbitals.In general, the colour that the we see is complementry to the colour absorbed.Different metal ion have different values of D, which explains why their complexes with the same ligand have different colour.Similarly, the crystal field splitting also depends on the nature of ligands and as the ligand for the same metal varies from H2O to NH3 to ethylenediamine, D for complexes increases. Accordingly, the electronic transition shifts to higher energy (shorter wavelength) as the ligand varies from H2O to NH3 to en, thus accounting for the variation in colour.Crystal field theory accounts for the magnetic properties of complexes in terms of the relative values of and the spin pairing energy P. Small values favour high spin complexes, and large Dvalues favour low spin complexes.Which of the following complexes are diamagnetic ? [Pt(NH3)4]2+ [Co(SCN)4]2- [Cu(en)2]2+ [HgI4]2-square planar tetrahedral square planar tetrahedral (i) (ii) (iii) (iv)

    Crystal field theory views the bonding in complexes as arising from electrostatic interaction and considers the effect of the ligand charges on the energies of the metal ion d-orbitals.In this theory, a ligand lone pair is modelled as a point negative charge that repels electrons in the d-orbitals of the central metal ion. The theory concentrated on the resulting splitting of the d-orbitals in two groups with different energies and used that splitting to rationalize and correlate the optical spectra, thermodynamic stability, and magnetic properties of complexes. This energy splitting between the two sets of dorbitals is called the crystal field splitting D.In general, the crystal field splitting energy D corresponds to wavelength of light in visible region of the spectrum, and colours of the complexes can therefore be attributed to electronic transition between the lower-and higher energy sets of d-orbitals.In general, the colour that the we see is complementry to the colour absorbed.Different metal ion have different values of D, which explains why their complexes with the same ligand have different colour.Similarly, the crystal field splitting also depends on the nature of ligands and as the ligand for the same metal varies from H2O to NH3 to ethylenediamine, D for complexes increases. Accordingly, the electronic transition shifts to higher energy (shorter wavelength) as the ligand varies from H2O to NH3 to en, thus accounting for the variation in colour.Crystal field theory accounts for the magnetic properties of complexes in terms of the relative values of and the spin pairing energy P. Small values favour high spin complexes, and large Dvalues favour low spin complexes.Which of the following statements is incorrect?

    If [Cu(H2O)4]2+absorbs a light of wavelength 600 nm for d-d transition, then the value of octahedral crystal field splitting energy for [Cu(H2O)6]2+will be ________ × 10-21J. (Nearest Integer)(Given: h = 6.63 × 10-34Js and c = 3.08 × 108ms-1)Correct answer is '766'. Can you explain this answer?
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    If [Cu(H2O)4]2+absorbs a light of wavelength 600 nm for d-d transition, then the value of octahedral crystal field splitting energy for [Cu(H2O)6]2+will be ________ × 10-21J. (Nearest Integer)(Given: h = 6.63 × 10-34Js and c = 3.08 × 108ms-1)Correct answer is '766'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If [Cu(H2O)4]2+absorbs a light of wavelength 600 nm for d-d transition, then the value of octahedral crystal field splitting energy for [Cu(H2O)6]2+will be ________ × 10-21J. (Nearest Integer)(Given: h = 6.63 × 10-34Js and c = 3.08 × 108ms-1)Correct answer is '766'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If [Cu(H2O)4]2+absorbs a light of wavelength 600 nm for d-d transition, then the value of octahedral crystal field splitting energy for [Cu(H2O)6]2+will be ________ × 10-21J. (Nearest Integer)(Given: h = 6.63 × 10-34Js and c = 3.08 × 108ms-1)Correct answer is '766'. Can you explain this answer?.
    Solutions for If [Cu(H2O)4]2+absorbs a light of wavelength 600 nm for d-d transition, then the value of octahedral crystal field splitting energy for [Cu(H2O)6]2+will be ________ × 10-21J. (Nearest Integer)(Given: h = 6.63 × 10-34Js and c = 3.08 × 108ms-1)Correct answer is '766'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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