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Consider an ideal vapour compression refrigeration cycle working on R-134a refrigerant. The COP of the cycle is 10 and the refrigeration capacity is 150 kJ/kg. The heat rejected by the refrigerant in the condenser is ______kJ/kg (round off to the nearest integer).
Correct answer is '165'. Can you explain this answer?
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Consider an ideal vapour compression refrigeration cycle working on R-...
Given : COP = 10, RC= 150 kJ/kg
Pin = 15 kJ/kg
= (150+ 15) = 165 kJ/kg
Pin = 15 kJ/kg
= (150+ 15) = 165 kJ/kg
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Consider an ideal vapour compression refrigeration cycle working on R-...
Given:
- COP (Coefficient of Performance) = 10
- Refrigeration capacity = 150 kJ/kg
To find:
- Heat rejected by the refrigerant in the condenser.
Explanation:
The Coefficient of Performance (COP) of a refrigeration cycle is defined as the ratio of the refrigeration capacity to the work input. Mathematically, it is given by:
COP = Refrigeration capacity / Work input
In an ideal vapor compression refrigeration cycle, the work input is the sum of the work done by the compressor (Wc) and the work done by the pump (Wp). Since the pump work is typically negligible compared to the compressor work, we can assume that the total work input is equal to the work done by the compressor.
So, in this case, the COP can be written as:
COP = Refrigeration capacity / Compressor work
Given that COP = 10 and refrigeration capacity = 150 kJ/kg, we can rearrange the equation to solve for the compressor work:
Compressor work = Refrigeration capacity / COP
Substituting the given values, we have:
Compressor work = 150 kJ/kg / 10
Compressor work = 15 kJ/kg
Heat rejected by the refrigerant in the condenser:
In an ideal vapor compression refrigeration cycle, the heat rejected by the refrigerant in the condenser is equal to the sum of the heat absorbed by the refrigerant in the evaporator (refrigeration capacity) and the work done by the compressor. Mathematically, it is given by:
Heat rejected = Refrigeration capacity + Compressor work
Substituting the values, we have:
Heat rejected = 150 kJ/kg + 15 kJ/kg
Heat rejected = 165 kJ/kg
Therefore, the heat rejected by the refrigerant in the condenser is 165 kJ/kg.
- COP (Coefficient of Performance) = 10
- Refrigeration capacity = 150 kJ/kg
To find:
- Heat rejected by the refrigerant in the condenser.
Explanation:
The Coefficient of Performance (COP) of a refrigeration cycle is defined as the ratio of the refrigeration capacity to the work input. Mathematically, it is given by:
COP = Refrigeration capacity / Work input
In an ideal vapor compression refrigeration cycle, the work input is the sum of the work done by the compressor (Wc) and the work done by the pump (Wp). Since the pump work is typically negligible compared to the compressor work, we can assume that the total work input is equal to the work done by the compressor.
So, in this case, the COP can be written as:
COP = Refrigeration capacity / Compressor work
Given that COP = 10 and refrigeration capacity = 150 kJ/kg, we can rearrange the equation to solve for the compressor work:
Compressor work = Refrigeration capacity / COP
Substituting the given values, we have:
Compressor work = 150 kJ/kg / 10
Compressor work = 15 kJ/kg
Heat rejected by the refrigerant in the condenser:
In an ideal vapor compression refrigeration cycle, the heat rejected by the refrigerant in the condenser is equal to the sum of the heat absorbed by the refrigerant in the evaporator (refrigeration capacity) and the work done by the compressor. Mathematically, it is given by:
Heat rejected = Refrigeration capacity + Compressor work
Substituting the values, we have:
Heat rejected = 150 kJ/kg + 15 kJ/kg
Heat rejected = 165 kJ/kg
Therefore, the heat rejected by the refrigerant in the condenser is 165 kJ/kg.
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Consider an ideal vapour compression refrigeration cycle working on R-134a refrigerant. The COP of the cycle is 10 and the refrigeration capacity is 150 kJ/kg. The heat rejected by the refrigerant in the condenser is ______kJ/kg (round off to the nearest integer).Correct answer is '165'. Can you explain this answer?
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Consider an ideal vapour compression refrigeration cycle working on R-134a refrigerant. The COP of the cycle is 10 and the refrigeration capacity is 150 kJ/kg. The heat rejected by the refrigerant in the condenser is ______kJ/kg (round off to the nearest integer).Correct answer is '165'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Consider an ideal vapour compression refrigeration cycle working on R-134a refrigerant. The COP of the cycle is 10 and the refrigeration capacity is 150 kJ/kg. The heat rejected by the refrigerant in the condenser is ______kJ/kg (round off to the nearest integer).Correct answer is '165'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider an ideal vapour compression refrigeration cycle working on R-134a refrigerant. The COP of the cycle is 10 and the refrigeration capacity is 150 kJ/kg. The heat rejected by the refrigerant in the condenser is ______kJ/kg (round off to the nearest integer).Correct answer is '165'. Can you explain this answer?.
Consider an ideal vapour compression refrigeration cycle working on R-134a refrigerant. The COP of the cycle is 10 and the refrigeration capacity is 150 kJ/kg. The heat rejected by the refrigerant in the condenser is ______kJ/kg (round off to the nearest integer).Correct answer is '165'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Consider an ideal vapour compression refrigeration cycle working on R-134a refrigerant. The COP of the cycle is 10 and the refrigeration capacity is 150 kJ/kg. The heat rejected by the refrigerant in the condenser is ______kJ/kg (round off to the nearest integer).Correct answer is '165'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider an ideal vapour compression refrigeration cycle working on R-134a refrigerant. The COP of the cycle is 10 and the refrigeration capacity is 150 kJ/kg. The heat rejected by the refrigerant in the condenser is ______kJ/kg (round off to the nearest integer).Correct answer is '165'. Can you explain this answer?.
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