JEE Exam > JEE Questions > A body is projected from the ground at an ang...
Start Learning for Free
A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)
Correct answer is '20'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A body is projected from the ground at an angle of 45° with the ho...
Degrees with the horizontal. Neglecting air resistance, the body will follow a parabolic path. The distance traveled by the body and the time taken to reach the maximum height can be calculated using the following equations:
- Range (R) = (v^2/g)*sin(2θ)
- Time of flight (T) = 2v*sin(θ)/g
Where v is the initial velocity of the body, θ is the angle of projection, and g is the acceleration due to gravity (approximately 9.81 m/s^2).
Assuming the initial velocity to be 10 m/s, we can calculate the range and time of flight as follows:
- R = (10^2/9.81)*sin(90) = 102.03 meters
- T = 2*10*sin(45)/9.81 = 1.45 seconds
Therefore, the body will travel a distance of 102.03 meters and reach the maximum height in 1.45 seconds.
- Range (R) = (v^2/g)*sin(2θ)
- Time of flight (T) = 2v*sin(θ)/g
Where v is the initial velocity of the body, θ is the angle of projection, and g is the acceleration due to gravity (approximately 9.81 m/s^2).
Assuming the initial velocity to be 10 m/s, we can calculate the range and time of flight as follows:
- R = (10^2/9.81)*sin(90) = 102.03 meters
- T = 2*10*sin(45)/9.81 = 1.45 seconds
Therefore, the body will travel a distance of 102.03 meters and reach the maximum height in 1.45 seconds.
Free Test
FREE
| Start Free Test |
Community Answer
A body is projected from the ground at an angle of 45° with the ho...
⇒ v cosα = u cos45° ...(i)
And v sinα = usin45° - gt ...(ii)
Solve for u.
u = 20√2m/s
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)Correct answer is '20'. Can you explain this answer?
Question Description
A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)Correct answer is '20'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)Correct answer is '20'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)Correct answer is '20'. Can you explain this answer?.
A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)Correct answer is '20'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)Correct answer is '20'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)Correct answer is '20'. Can you explain this answer?.
Solutions for A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)Correct answer is '20'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)Correct answer is '20'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)Correct answer is '20'. Can you explain this answer?, a detailed solution for A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)Correct answer is '20'. Can you explain this answer? has been provided alongside types of A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)Correct answer is '20'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A body is projected from the ground at an angle of 45° with the horizontal. Its velocity after 2 s is 20 ms-1. The maximum height reached by the body during its motion is ________ m. (Use g = 10 ms-2). (In integers)Correct answer is '20'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup