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A relation in which every non-key attribute is fully functionally dependent on the primary key and which has no transitive dependencies is in -
  • a)
    3NF
  • b)
    BCNF
  • c)
    5NF
  • d)
    4NF
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A relation in which every non-key attribute is fully functionally depe...
1NF:
  • There are only Single Valued Attributes.
  • There is a unique name for every Attribute/Column.
2NF:
  • A relation that is in First Normal Form 
  • Every non-primary-key attribute is fully functionally dependent on the primary key 
3NF
  • The third normal form is based on the concept of transitive dependency. A functional dependency X->Y in a relation schema R is a transitive dependency if there exists a set of attributed Z in R that is neither a candidate key nor a subset of any key of R.
  • A relation is in 3NF if it satisfies 2NF and no prime attribute of R is transitively dependent on the primary key.
  • If X - > A is a functional dependency, then A should be a prime attribute or X should be a candidate key.
  • Lossless join and dependency preservation is always possible in 3NF. 3NF decomposition is always lossless join and dependency preserving.
BCNF:
  • It stands for Boyce Codd normal form.
  • A relation R is in BCNF if whenever a non-trivial functional dependency X -> A holds in R, then X is a superkey of R. Any relation with two attributes is always in BCNF. Because when a relation contains only two attributes then one attribute determines another and the left side of the functional dependency will always be a candidate key in that case.
  • BCNF is not always dependency preserving.
Therefore the answer is Option 1.
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A relation in which every non-key attribute is fully functionally dependent on the primary key and which has no transitive dependencies is in -a)3NFb)BCNFc)5NFd)4NFCorrect answer is option 'A'. Can you explain this answer?
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