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At 300 K, a sample of 3.0 g of gas A occupies the same volume as 0.2 g of hydrogen at 200 K at the same pressure. The molar mass of gas A is ______ g mol-1. (Nearest integer)
Assume that the behaviour of gases as ideal. (Given: The molar mass of hydrogen (H2) gas is 2.0 g mol-1)
    Correct answer is '45'. Can you explain this answer?
    Most Upvoted Answer
    At 300 K, a sample of 3.0 g of gas A occupies the same volume as 0.2 g...
    V1, Volume of 0.2 g H2 at 200 K 
    V2, Volume of 3.0 g of gas A at 300 
    V1 = V2 (Given)

    ∴  M = 45 g mol-1
    Free Test
    Community Answer
    At 300 K, a sample of 3.0 g of gas A occupies the same volume as 0.2 g...
    Given:
    - Temperature of gas A, TA = 300 K
    - Temperature of hydrogen, TH = 200 K
    - Mass of gas A, mA = 3.0 g
    - Mass of hydrogen, mH = 0.2 g
    - Molar mass of hydrogen, MH = 2.0 g/mol

    Assumptions:
    - The gases behave ideally.
    - The pressure is constant.

    Key Formula:
    The ideal gas equation is given by PV = nRT, where:
    - P is the pressure
    - V is the volume
    - n is the number of moles
    - R is the ideal gas constant
    - T is the temperature

    Approach:
    1. Calculate the number of moles of hydrogen using the equation n = m/M, where m is the mass and M is the molar mass.
    2. Use the ideal gas equation for hydrogen to find the volume occupied by hydrogen at 200 K.
    3. Use the ideal gas equation for gas A to find the number of moles of gas A.
    4. Use the equation n = m/M to find the molar mass of gas A.

    Calculations:
    1. Number of moles of hydrogen:
    nH = mH/MH = 0.2 g / 2.0 g/mol = 0.1 mol

    2. Volume occupied by hydrogen at 200 K:
    PV = nRT
    VH = nHRTH/P
    = (0.1 mol) * (0.0821 L·atm/(mol·K)) * (200 K) / P

    3. Number of moles of gas A:
    PV = nRT
    nA = PV/RT
    = (P * VH * TA) / (P * R * TH)
    = VH * (TA / TH)

    4. Molar mass of gas A:
    nA = mA/MA
    MA = mA / nA
    = 3.0 g / nA

    5. Substitute the value of nA from step 3:
    MA = 3.0 g / (VH * (TA / TH))

    Final Answer:
    After substituting the values, we get:
    MA = 3.0 g / (VH * (TA / TH))
    = 3.0 g / ((0.1 mol) *
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    At 300 K, a sample of 3.0 g of gas A occupies the same volume as 0.2 g of hydrogen at 200 K at the same pressure. The molar mass of gas A is ______ g mol-1. (Nearest integer)Assume that the behaviour of gases as ideal. (Given: The molar mass of hydrogen (H2) gas is 2.0 g mol-1)Correct answer is '45'. Can you explain this answer?
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    At 300 K, a sample of 3.0 g of gas A occupies the same volume as 0.2 g of hydrogen at 200 K at the same pressure. The molar mass of gas A is ______ g mol-1. (Nearest integer)Assume that the behaviour of gases as ideal. (Given: The molar mass of hydrogen (H2) gas is 2.0 g mol-1)Correct answer is '45'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about At 300 K, a sample of 3.0 g of gas A occupies the same volume as 0.2 g of hydrogen at 200 K at the same pressure. The molar mass of gas A is ______ g mol-1. (Nearest integer)Assume that the behaviour of gases as ideal. (Given: The molar mass of hydrogen (H2) gas is 2.0 g mol-1)Correct answer is '45'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 300 K, a sample of 3.0 g of gas A occupies the same volume as 0.2 g of hydrogen at 200 K at the same pressure. The molar mass of gas A is ______ g mol-1. (Nearest integer)Assume that the behaviour of gases as ideal. (Given: The molar mass of hydrogen (H2) gas is 2.0 g mol-1)Correct answer is '45'. Can you explain this answer?.
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