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At 25°C, 50 g of iron reacts with HCI to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is ________ J.
(Round off to the nearest integer) [Given: R = 8.314 J mol-1 K-1. Assume, hydrogen is an ideal gas]
[Atomic mass of Fe is 55.85 u]
(Round off to the nearest integer) [Given: R = 8.314 J mol-1 K-1. Assume, hydrogen is an ideal gas]
[Atomic mass of Fe is 55.85 u]
Correct answer is '2218'. Can you explain this answer?
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At 25°C, 50 g of iron reacts with HCI to form FeCl2. The evolved h...
T = 298 K, R = 8.314 
→ Chemicl reaction is:
Fe + 2HCI → FeCl2 + H2(g)
50g P = 1 bar
= 50/55.85 mol
→ Work done for 1 mol gas
= -Pext × ΔV
= Δ ng RT
= -1 × 8.314 × 298 J
→ Work done for 50/55.85 mol gas
When work done is negative, expansion of the gas takes place.
So, the correct answer is 2218.
→ Chemicl reaction is:
Fe + 2HCI → FeCl2 + H2(g)
50g P = 1 bar
= 50/55.85 mol
→ Work done for 1 mol gas
= -Pext × ΔV
= Δ ng RT
= -1 × 8.314 × 298 J
→ Work done for 50/55.85 mol gas
When work done is negative, expansion of the gas takes place.
So, the correct answer is 2218.
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At 25°C, 50 g of iron reacts with HCI to form FeCl2. The evolved h...
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At 25°C, 50 g of iron reacts with HCI to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is ________ J.(Round off to the nearest integer) [Given: R = 8.314 J mol-1 K-1. Assume, hydrogen is an ideal gas][Atomic mass of Fe is 55.85 u]Correct answer is '2218'. Can you explain this answer?
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At 25°C, 50 g of iron reacts with HCI to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is ________ J.(Round off to the nearest integer) [Given: R = 8.314 J mol-1 K-1. Assume, hydrogen is an ideal gas][Atomic mass of Fe is 55.85 u]Correct answer is '2218'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about At 25°C, 50 g of iron reacts with HCI to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is ________ J.(Round off to the nearest integer) [Given: R = 8.314 J mol-1 K-1. Assume, hydrogen is an ideal gas][Atomic mass of Fe is 55.85 u]Correct answer is '2218'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 25°C, 50 g of iron reacts with HCI to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is ________ J.(Round off to the nearest integer) [Given: R = 8.314 J mol-1 K-1. Assume, hydrogen is an ideal gas][Atomic mass of Fe is 55.85 u]Correct answer is '2218'. Can you explain this answer?.
At 25°C, 50 g of iron reacts with HCI to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is ________ J.(Round off to the nearest integer) [Given: R = 8.314 J mol-1 K-1. Assume, hydrogen is an ideal gas][Atomic mass of Fe is 55.85 u]Correct answer is '2218'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about At 25°C, 50 g of iron reacts with HCI to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is ________ J.(Round off to the nearest integer) [Given: R = 8.314 J mol-1 K-1. Assume, hydrogen is an ideal gas][Atomic mass of Fe is 55.85 u]Correct answer is '2218'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 25°C, 50 g of iron reacts with HCI to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is ________ J.(Round off to the nearest integer) [Given: R = 8.314 J mol-1 K-1. Assume, hydrogen is an ideal gas][Atomic mass of Fe is 55.85 u]Correct answer is '2218'. Can you explain this answer?.
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At 25°C, 50 g of iron reacts with HCI to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is ________ J.(Round off to the nearest integer) [Given: R = 8.314 J mol-1 K-1. Assume, hydrogen is an ideal gas][Atomic mass of Fe is 55.85 u]Correct answer is '2218'. Can you explain this answer?, a detailed solution for At 25°C, 50 g of iron reacts with HCI to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is ________ J.(Round off to the nearest integer) [Given: R = 8.314 J mol-1 K-1. Assume, hydrogen is an ideal gas][Atomic mass of Fe is 55.85 u]Correct answer is '2218'. Can you explain this answer? has been provided alongside types of At 25°C, 50 g of iron reacts with HCI to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is ________ J.(Round off to the nearest integer) [Given: R = 8.314 J mol-1 K-1. Assume, hydrogen is an ideal gas][Atomic mass of Fe is 55.85 u]Correct answer is '2218'. Can you explain this answer? theory, EduRev gives you an
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