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A company dissolves 'x' amount of CO2 at 298 K in 1 litre of water to prepare soda water. x = _____ × 10-3 g. (Nearest integer)
(Given: Partial pressure of CO2 at 298 K = 0.835 bar
Henry's law constant for CO2 at 298 K = 1.67 k bar. Atomic mass of H, C and O is 1, 12, and 6 g mol-1, respectively)
    Correct answer is '1221'. Can you explain this answer?
    Most Upvoted Answer
    A company dissolves x amount of CO2 at 298 K in 1 litre of water to pr...
    To prepare soda water, the company dissolves x amount of CO2 in 1 litre of water at 298 K.

    However, the value of x is not provided in the question, so it is impossible to determine the exact amount of CO2 dissolved without additional information.
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    Community Answer
    A company dissolves x amount of CO2 at 298 K in 1 litre of water to pr...
    Let mole fraction of CO2 = x1  

    KH = 1.67 k bar = 1.67 × 103 bar
    p = 0.835 bar

    n1 = 0.5 × 10-3n1 + 27.77 × 10-3  
    n1(1 - 0.5 × 10-3) = 27.77 × 10-3   

    n1 = 0.027 mole
    Weight of CO2 dissolved = 0.027 × 44
    = 1.221 gm
    = 1221 × 10-3 gm
    x = 1221
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    A company dissolves x amount of CO2 at 298 K in 1 litre of water to prepare soda water. x = _____ × 10-3 g. (Nearest integer)(Given: Partial pressure of CO2 at 298 K = 0.835 barHenrys law constant for CO2 at 298 K = 1.67 k bar. Atomic mass of H, C and O is 1, 12, and 6 g mol-1, respectively)Correct answer is '1221'. Can you explain this answer?
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    A company dissolves x amount of CO2 at 298 K in 1 litre of water to prepare soda water. x = _____ × 10-3 g. (Nearest integer)(Given: Partial pressure of CO2 at 298 K = 0.835 barHenrys law constant for CO2 at 298 K = 1.67 k bar. Atomic mass of H, C and O is 1, 12, and 6 g mol-1, respectively)Correct answer is '1221'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A company dissolves x amount of CO2 at 298 K in 1 litre of water to prepare soda water. x = _____ × 10-3 g. (Nearest integer)(Given: Partial pressure of CO2 at 298 K = 0.835 barHenrys law constant for CO2 at 298 K = 1.67 k bar. Atomic mass of H, C and O is 1, 12, and 6 g mol-1, respectively)Correct answer is '1221'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A company dissolves x amount of CO2 at 298 K in 1 litre of water to prepare soda water. x = _____ × 10-3 g. (Nearest integer)(Given: Partial pressure of CO2 at 298 K = 0.835 barHenrys law constant for CO2 at 298 K = 1.67 k bar. Atomic mass of H, C and O is 1, 12, and 6 g mol-1, respectively)Correct answer is '1221'. Can you explain this answer?.
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