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If O2 gas is bubbled through water at 303 K, the number of millimoles of O2 gas that dissolve in 1 litre of water is _________. (Nearest integer)
(Given: Henry's Law constant for O2 at 303 K is 46.82 k bar and partial pressure of O2 = 0.920 bar)
(Assume solubility of O2 in water is too small, nearly negligible)
(Given: Henry's Law constant for O2 at 303 K is 46.82 k bar and partial pressure of O2 = 0.920 bar)
(Assume solubility of O2 in water is too small, nearly negligible)
Correct answer is '1'. Can you explain this answer?
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Henry's Law:
Henry's Law states that the amount of gas dissolved in a liquid is directly proportional to the partial pressure of the gas above the liquid. Mathematically, it can be represented as:
\[ C = k \times P \]
Where:
- C is the concentration of the gas in the solution
- k is the Henry's Law constant
- P is the partial pressure of the gas
Calculating the Concentration of O2 in Water:
Given:
- Henry's Law constant (k) for O2 at 303 K is 46.82 k bar
- Partial pressure of O2 (P) = 0.920 bar
Using Henry's Law equation:
\[ C = 46.82 \times 0.920 \]
\[ C = 43.06 \text{ mmol/L} \]
Rounding off:
Since the solubility of O2 in water is considered to be very small and nearly negligible, we can round off the concentration to the nearest integer.
\[ 43.06 \approx 43 \text{ mmol/L} \]
Therefore, the number of millimoles of O2 gas that dissolve in 1 litre of water at 303 K when O2 gas is bubbled through it is 43 mmol/L, which rounds off to 1 when considering the negligible solubility of O2 in water.
Henry's Law states that the amount of gas dissolved in a liquid is directly proportional to the partial pressure of the gas above the liquid. Mathematically, it can be represented as:
\[ C = k \times P \]
Where:
- C is the concentration of the gas in the solution
- k is the Henry's Law constant
- P is the partial pressure of the gas
Calculating the Concentration of O2 in Water:
Given:
- Henry's Law constant (k) for O2 at 303 K is 46.82 k bar
- Partial pressure of O2 (P) = 0.920 bar
Using Henry's Law equation:
\[ C = 46.82 \times 0.920 \]
\[ C = 43.06 \text{ mmol/L} \]
Rounding off:
Since the solubility of O2 in water is considered to be very small and nearly negligible, we can round off the concentration to the nearest integer.
\[ 43.06 \approx 43 \text{ mmol/L} \]
Therefore, the number of millimoles of O2 gas that dissolve in 1 litre of water at 303 K when O2 gas is bubbled through it is 43 mmol/L, which rounds off to 1 when considering the negligible solubility of O2 in water.
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If O2gas is bubbled through water at 303 K, the number of millimoles of O2gas that dissolve in 1 litre of water is _________. (Nearest integer)(Given: Henrys Law constant for O2at 303 K is 46.82 k bar and partial pressure of O2= 0.920 bar)(Assume solubility of O2in water is too small, nearly negligible)Correct answer is '1'. Can you explain this answer?
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If O2gas is bubbled through water at 303 K, the number of millimoles of O2gas that dissolve in 1 litre of water is _________. (Nearest integer)(Given: Henrys Law constant for O2at 303 K is 46.82 k bar and partial pressure of O2= 0.920 bar)(Assume solubility of O2in water is too small, nearly negligible)Correct answer is '1'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If O2gas is bubbled through water at 303 K, the number of millimoles of O2gas that dissolve in 1 litre of water is _________. (Nearest integer)(Given: Henrys Law constant for O2at 303 K is 46.82 k bar and partial pressure of O2= 0.920 bar)(Assume solubility of O2in water is too small, nearly negligible)Correct answer is '1'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If O2gas is bubbled through water at 303 K, the number of millimoles of O2gas that dissolve in 1 litre of water is _________. (Nearest integer)(Given: Henrys Law constant for O2at 303 K is 46.82 k bar and partial pressure of O2= 0.920 bar)(Assume solubility of O2in water is too small, nearly negligible)Correct answer is '1'. Can you explain this answer?.
If O2gas is bubbled through water at 303 K, the number of millimoles of O2gas that dissolve in 1 litre of water is _________. (Nearest integer)(Given: Henrys Law constant for O2at 303 K is 46.82 k bar and partial pressure of O2= 0.920 bar)(Assume solubility of O2in water is too small, nearly negligible)Correct answer is '1'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If O2gas is bubbled through water at 303 K, the number of millimoles of O2gas that dissolve in 1 litre of water is _________. (Nearest integer)(Given: Henrys Law constant for O2at 303 K is 46.82 k bar and partial pressure of O2= 0.920 bar)(Assume solubility of O2in water is too small, nearly negligible)Correct answer is '1'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If O2gas is bubbled through water at 303 K, the number of millimoles of O2gas that dissolve in 1 litre of water is _________. (Nearest integer)(Given: Henrys Law constant for O2at 303 K is 46.82 k bar and partial pressure of O2= 0.920 bar)(Assume solubility of O2in water is too small, nearly negligible)Correct answer is '1'. Can you explain this answer?.
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