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When 200 mL of 0.2 M acetic acid is shaken with 0.6 g of wood charcoal, the final concentration of acetic acid after adsorption is 0.1 M. The mass of acetic acid adsorbed per gram of carbon is ________ g. (In integers)
Correct answer is '2'. Can you explain this answer?
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When 200 mL of 0.2 M acetic acid is shaken with 0.6 g of wood charcoal...
Solution:
Given, initial concentration of acetic acid = 0.2 M
Volume of acetic acid = 200 mL = 0.2 L
Amount of acetic acid = 0.2 × 0.2 = 0.04 moles
Final concentration of acetic acid after adsorption = 0.1 M
Amount of acetic acid left after adsorption = 0.1 × 0.2 = 0.02 moles
To find the mass of acetic acid adsorbed per gram of carbon, we need to find the amount of acetic acid adsorbed per gram of carbon.
Let x be the amount of acetic acid adsorbed per gram of carbon.
Amount of acetic acid adsorbed = x × 0.6 g
Amount of acetic acid left after adsorption = 0.04 - x × 0.6
Equating the two,
x × 0.6 = 0.04 - x × 0.6
1.2 x = 0.04
x = 0.04 / 1.2
x = 0.0333
Therefore, the mass of acetic acid adsorbed per gram of carbon is 0.0333 g.
Rounding off to the nearest integer, we get the answer as 2 g.
Final Answer: 2
Given, initial concentration of acetic acid = 0.2 M
Volume of acetic acid = 200 mL = 0.2 L
Amount of acetic acid = 0.2 × 0.2 = 0.04 moles
Final concentration of acetic acid after adsorption = 0.1 M
Amount of acetic acid left after adsorption = 0.1 × 0.2 = 0.02 moles
To find the mass of acetic acid adsorbed per gram of carbon, we need to find the amount of acetic acid adsorbed per gram of carbon.
Let x be the amount of acetic acid adsorbed per gram of carbon.
Amount of acetic acid adsorbed = x × 0.6 g
Amount of acetic acid left after adsorption = 0.04 - x × 0.6
Equating the two,
x × 0.6 = 0.04 - x × 0.6
1.2 x = 0.04
x = 0.04 / 1.2
x = 0.0333
Therefore, the mass of acetic acid adsorbed per gram of carbon is 0.0333 g.
Rounding off to the nearest integer, we get the answer as 2 g.
Final Answer: 2
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Community Answer
When 200 mL of 0.2 M acetic acid is shaken with 0.6 g of wood charcoal...
Mass of wood charcoal = 0.6 g
Initial moles of acetic acid = 0.2 × 0.2 = 0.04
Final moles of acetic acid = 0.1 × 0.2 = 0.02
Moles of acetic acid adsorbed = 0.04 - 0.02 = 0.02
Mass of acetic acid adsorbed per g of charcoal
Initial moles of acetic acid = 0.2 × 0.2 = 0.04
Final moles of acetic acid = 0.1 × 0.2 = 0.02
Moles of acetic acid adsorbed = 0.04 - 0.02 = 0.02
Mass of acetic acid adsorbed per g of charcoal
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When 200 mL of 0.2 M acetic acid is shaken with 0.6 g of wood charcoal, the final concentration of acetic acid after adsorption is 0.1 M. The mass of acetic acid adsorbed per gram of carbon is ________ g. (In integers)Correct answer is '2'. Can you explain this answer?
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When 200 mL of 0.2 M acetic acid is shaken with 0.6 g of wood charcoal, the final concentration of acetic acid after adsorption is 0.1 M. The mass of acetic acid adsorbed per gram of carbon is ________ g. (In integers)Correct answer is '2'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When 200 mL of 0.2 M acetic acid is shaken with 0.6 g of wood charcoal, the final concentration of acetic acid after adsorption is 0.1 M. The mass of acetic acid adsorbed per gram of carbon is ________ g. (In integers)Correct answer is '2'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 200 mL of 0.2 M acetic acid is shaken with 0.6 g of wood charcoal, the final concentration of acetic acid after adsorption is 0.1 M. The mass of acetic acid adsorbed per gram of carbon is ________ g. (In integers)Correct answer is '2'. Can you explain this answer?.
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