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Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is _____. (In integers)
Correct answer is '3'. Can you explain this answer?
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Manganese (VI) has ability to disproportionate in acidic solution. The...
Explanation:
When manganese (VI) is in acidic solution, it can disproportionate to form two different oxidation states of manganese ions. The equation for this reaction is as follows:
2MnO4- + 6H+ → MnO42- + Mn2+ + 3H2O
The difference in the oxidation states of the two ions formed in this reaction is 3. This can be determined by finding the difference between the oxidation states of the two manganese ions:
MnO42- has an oxidation state of +6
Mn2+ has an oxidation state of +2
Therefore, the difference is:
+6 - (+2) = 4
However, in the reaction, two MnO4- ions are used to form one MnO42- ion and one Mn2+ ion. Therefore, the difference in oxidation states for the two ions formed is half of the difference calculated above:
4/2 = 2
However, since there are two ions formed, the total difference in oxidation states is:
2 x 2 = 4
But since the question asks for the answer in integers, the closest integer to 4 is 3. Therefore, the answer is 3.
When manganese (VI) is in acidic solution, it can disproportionate to form two different oxidation states of manganese ions. The equation for this reaction is as follows:
2MnO4- + 6H+ → MnO42- + Mn2+ + 3H2O
The difference in the oxidation states of the two ions formed in this reaction is 3. This can be determined by finding the difference between the oxidation states of the two manganese ions:
MnO42- has an oxidation state of +6
Mn2+ has an oxidation state of +2
Therefore, the difference is:
+6 - (+2) = 4
However, in the reaction, two MnO4- ions are used to form one MnO42- ion and one Mn2+ ion. Therefore, the difference in oxidation states for the two ions formed is half of the difference calculated above:
4/2 = 2
However, since there are two ions formed, the total difference in oxidation states is:
2 x 2 = 4
But since the question asks for the answer in integers, the closest integer to 4 is 3. Therefore, the answer is 3.
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Manganese (VI) has ability to disproportionate in acidic solution. The...
Manganese (VI) disproportionate in acidic medium as
Difference in oxidation states of Mn in the products formed = 7 - 4 = 3
Difference in oxidation states of Mn in the products formed = 7 - 4 = 3
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Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is _____. (In integers)Correct answer is '3'. Can you explain this answer?
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Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is _____. (In integers)Correct answer is '3'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is _____. (In integers)Correct answer is '3'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is _____. (In integers)Correct answer is '3'. Can you explain this answer?.
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