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The oxidation state of manganese in the product obtained in a reaction of potassium permanganate and hydrogen peroxide in basic medium is ______. (In integer)
Correct answer is '4'. Can you explain this answer?
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The oxidation state of manganese in the product obtained in a reaction of potassium permanganate (KMnO4) and hydrogen peroxide (H2O2) in a basic medium is +4.
Explanation:
Potassium permanganate is a strong oxidizing agent and in a basic medium, it reacts with hydrogen peroxide to form a brown precipitate of manganese dioxide (MnO2).
The reaction can be represented as follows:
2KMnO4 + 3H2O2 + 2KOH → 2MnO2 + 3H2O + 2K2O
In this reaction, the oxidation state of manganese changes from +7 in KMnO4 to +4 in MnO2. Let's understand the changes in oxidation state step by step:
1. Potassium permanganate (KMnO4):
The oxidation state of potassium (K) is +1. Oxygen (O) has a fixed oxidation state of -2. So, let's assume the oxidation state of manganese (Mn) as x.
Therefore, (+1) + x + 4(-2) = 0
Simplifying the above equation, we get:
x - 8 = 0
x = +8
Thus, the oxidation state of manganese in KMnO4 is +7.
2. Manganese dioxide (MnO2):
The oxidation state of oxygen (O) is -2. Since there are two oxygen atoms, the total oxidation state due to oxygen is -4.
Let's assume the oxidation state of manganese (Mn) as y.
Therefore, y + 2(-2) = 0
Simplifying the above equation, we get:
y - 4 = 0
y = +4
Thus, the oxidation state of manganese in MnO2 is +4.
Conclusion:
In the reaction between potassium permanganate and hydrogen peroxide in a basic medium, the oxidation state of manganese changes from +7 in KMnO4 to +4 in MnO2. Hence, the correct answer is +4.
Explanation:
Potassium permanganate is a strong oxidizing agent and in a basic medium, it reacts with hydrogen peroxide to form a brown precipitate of manganese dioxide (MnO2).
The reaction can be represented as follows:
2KMnO4 + 3H2O2 + 2KOH → 2MnO2 + 3H2O + 2K2O
In this reaction, the oxidation state of manganese changes from +7 in KMnO4 to +4 in MnO2. Let's understand the changes in oxidation state step by step:
1. Potassium permanganate (KMnO4):
The oxidation state of potassium (K) is +1. Oxygen (O) has a fixed oxidation state of -2. So, let's assume the oxidation state of manganese (Mn) as x.
Therefore, (+1) + x + 4(-2) = 0
Simplifying the above equation, we get:
x - 8 = 0
x = +8
Thus, the oxidation state of manganese in KMnO4 is +7.
2. Manganese dioxide (MnO2):
The oxidation state of oxygen (O) is -2. Since there are two oxygen atoms, the total oxidation state due to oxygen is -4.
Let's assume the oxidation state of manganese (Mn) as y.
Therefore, y + 2(-2) = 0
Simplifying the above equation, we get:
y - 4 = 0
y = +4
Thus, the oxidation state of manganese in MnO2 is +4.
Conclusion:
In the reaction between potassium permanganate and hydrogen peroxide in a basic medium, the oxidation state of manganese changes from +7 in KMnO4 to +4 in MnO2. Hence, the correct answer is +4.
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The oxidation state of manganese in the product obtained in a reaction of potassium permanganate and hydrogen peroxide in basic medium is ______. (In integer)Correct answer is '4'. Can you explain this answer?
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The oxidation state of manganese in the product obtained in a reaction of potassium permanganate and hydrogen peroxide in basic medium is ______. (In integer)Correct answer is '4'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The oxidation state of manganese in the product obtained in a reaction of potassium permanganate and hydrogen peroxide in basic medium is ______. (In integer)Correct answer is '4'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The oxidation state of manganese in the product obtained in a reaction of potassium permanganate and hydrogen peroxide in basic medium is ______. (In integer)Correct answer is '4'. Can you explain this answer?.
The oxidation state of manganese in the product obtained in a reaction of potassium permanganate and hydrogen peroxide in basic medium is ______. (In integer)Correct answer is '4'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The oxidation state of manganese in the product obtained in a reaction of potassium permanganate and hydrogen peroxide in basic medium is ______. (In integer)Correct answer is '4'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The oxidation state of manganese in the product obtained in a reaction of potassium permanganate and hydrogen peroxide in basic medium is ______. (In integer)Correct answer is '4'. Can you explain this answer?.
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