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A resistance spot welding of two 1.55 mm thick metal sheets is performed using welding current of 10000 A for 0.25 second. The contact resistance at the interface of the metal sheets is 0.0001Ω. The volume of weld nugget formed after welding is 70 mm3. Considering the heat required to melt unit volume of metal is 12 J/mm3, the thermal efficiency of the welding process is_________ %  (round off to one decimal place). 
    Correct answer is '33.6'. Can you explain this answer?
    Most Upvoted Answer
    A resistance spot welding of two 1.55 mm thick metal sheets is perform...
    Given :
    t = 1.55 mm ,
    I = 10000 A
    T = 0.25 sec ,
    R = 0.0001Ω
    V = 70 mm3
    Specific heat required for melting = 12 J/mm3

    =  33.6%
    Free Test
    Community Answer
    A resistance spot welding of two 1.55 mm thick metal sheets is perform...
    To calculate the heat generated during the resistance spot welding, we can use the formula:

    Q = I^2 * R * t

    Where:
    Q = heat generated (in Joules)
    I = welding current (in Amperes)
    R = contact resistance (in Ohms)
    t = time (in seconds)

    Plugging in the given values:
    I = 10000 A
    R = 0.0001 Ohms
    t = 0.25 s

    Q = (10000^2) * 0.0001 * 0.25
    Q = 2500 Joules

    Therefore, the heat generated during the resistance spot welding is 2500 Joules.
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    A resistance spot welding of two 1.55 mm thick metal sheets is performed using welding current of 10000 A for 0.25 second. The contact resistance at the interface of the metal sheets is 0.0001Ω. The volume of weld nugget formed after welding is 70 mm3. Considering the heat required to melt unit volume of metal is 12 J/mm3, the thermal efficiency of the welding process is_________ % (round off to one decimal place).Correct answer is '33.6'. Can you explain this answer?
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    A resistance spot welding of two 1.55 mm thick metal sheets is performed using welding current of 10000 A for 0.25 second. The contact resistance at the interface of the metal sheets is 0.0001Ω. The volume of weld nugget formed after welding is 70 mm3. Considering the heat required to melt unit volume of metal is 12 J/mm3, the thermal efficiency of the welding process is_________ % (round off to one decimal place).Correct answer is '33.6'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A resistance spot welding of two 1.55 mm thick metal sheets is performed using welding current of 10000 A for 0.25 second. The contact resistance at the interface of the metal sheets is 0.0001Ω. The volume of weld nugget formed after welding is 70 mm3. Considering the heat required to melt unit volume of metal is 12 J/mm3, the thermal efficiency of the welding process is_________ % (round off to one decimal place).Correct answer is '33.6'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A resistance spot welding of two 1.55 mm thick metal sheets is performed using welding current of 10000 A for 0.25 second. The contact resistance at the interface of the metal sheets is 0.0001Ω. The volume of weld nugget formed after welding is 70 mm3. Considering the heat required to melt unit volume of metal is 12 J/mm3, the thermal efficiency of the welding process is_________ % (round off to one decimal place).Correct answer is '33.6'. Can you explain this answer?.
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