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Consider a steam power plant operating on an ideal reheat Rankine cycle. The work input to the pump is  20kJ/kg. The work output from the high pressure turbine is 750 kJ/kg. The work output from the low pressure turbine is 1500 kJ/kg. The thermal efficiency of the cycle is 50%. The enthalpy of saturated liquid and saturated vapour at condenser pressure are 200 kJ/kg and 2600 kJ/kg, respectively. The quality of steam at the exit of the low pressure turbine is _______ %(round off to the nearest integer). 
    Correct answer is '92.91'. Can you explain this answer?
    Most Upvoted Answer
    Consider a steam power plant operating on an ideal reheat Rankine cycl...
    Given :



    QR = 2230 kJ/kg
    QR = h4− h5 = 2230 kJ/kg
    For condenser pressure 

    2230 = x(2600− 200)
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    Community Answer
    Consider a steam power plant operating on an ideal reheat Rankine cycl...
    Given data:
    - Work input to the pump (Win) = 20 kJ/kg
    - Work output from the high-pressure turbine (WoutHP) = 750 kJ/kg
    - Work output from the low-pressure turbine (WoutLP) = 1500 kJ/kg
    - Thermal efficiency (η) = 50%
    - Enthalpy of saturated liquid at condenser pressure (hliquid) = 200 kJ/kg
    - Enthalpy of saturated vapor at condenser pressure (hvapor) = 2600 kJ/kg

    Calculating enthalpy at high-pressure turbine exit:
    The enthalpy at the high-pressure turbine exit (h2) can be calculated using the equation:

    η = (WoutHP - Win) / (h2 - h1)

    Rearranging the equation, we have:

    h2 = h1 + (WoutHP - Win) / η

    Substituting the given values, we get:

    h2 = 200 + (750 - 20) / 0.5
    h2 = 200 + 1460
    h2 = 1660 kJ/kg

    Calculating enthalpy at low-pressure turbine exit:
    The enthalpy at the low-pressure turbine exit (h3) can be calculated using the equation:

    η = (WoutLP - WoutHP) / (h3 - h2)

    Rearranging the equation, we have:

    h3 = h2 + (WoutLP - WoutHP) / η

    Substituting the given values, we get:

    h3 = 1660 + (1500 - 750) / 0.5
    h3 = 1660 + 1500
    h3 = 3160 kJ/kg

    Calculating the quality of steam at the exit of the low-pressure turbine:
    The quality of steam (x) can be calculated using the equation:

    x = (h - hliquid) / (hvapor - hliquid)

    Substituting the given values, we get:

    x = (3160 - 200) / (2600 - 200)
    x = 2960 / 2400
    x = 1.2333

    The quality of steam is given as a decimal value, so we need to convert it to a percentage:

    Quality (%) = x * 100
    Quality (%) = 1.2333 * 100
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    Consider a steam power plant operating on an ideal reheat Rankine cycle. The work input to the pump is 20kJ/kg. The work output from the high pressure turbine is 750 kJ/kg. The work output from the low pressure turbine is 1500 kJ/kg. The thermal efficiency of the cycle is 50%. The enthalpy of saturated liquid and saturated vapour at condenser pressure are 200 kJ/kg and 2600 kJ/kg, respectively. The quality of steam at the exit of the low pressure turbine is _______ %(round off to the nearest integer).Correct answer is '92.91'. Can you explain this answer?
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    Consider a steam power plant operating on an ideal reheat Rankine cycle. The work input to the pump is 20kJ/kg. The work output from the high pressure turbine is 750 kJ/kg. The work output from the low pressure turbine is 1500 kJ/kg. The thermal efficiency of the cycle is 50%. The enthalpy of saturated liquid and saturated vapour at condenser pressure are 200 kJ/kg and 2600 kJ/kg, respectively. The quality of steam at the exit of the low pressure turbine is _______ %(round off to the nearest integer).Correct answer is '92.91'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Consider a steam power plant operating on an ideal reheat Rankine cycle. The work input to the pump is 20kJ/kg. The work output from the high pressure turbine is 750 kJ/kg. The work output from the low pressure turbine is 1500 kJ/kg. The thermal efficiency of the cycle is 50%. The enthalpy of saturated liquid and saturated vapour at condenser pressure are 200 kJ/kg and 2600 kJ/kg, respectively. The quality of steam at the exit of the low pressure turbine is _______ %(round off to the nearest integer).Correct answer is '92.91'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a steam power plant operating on an ideal reheat Rankine cycle. The work input to the pump is 20kJ/kg. The work output from the high pressure turbine is 750 kJ/kg. The work output from the low pressure turbine is 1500 kJ/kg. The thermal efficiency of the cycle is 50%. The enthalpy of saturated liquid and saturated vapour at condenser pressure are 200 kJ/kg and 2600 kJ/kg, respectively. The quality of steam at the exit of the low pressure turbine is _______ %(round off to the nearest integer).Correct answer is '92.91'. Can you explain this answer?.
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