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A rigid insulated tank is initially evacuated. It is connected through a valve to supply line that carries air at a constant pressure and temperature of 250 kPa and 400 K respectively. Now the valve is opened and air is allowed to flow into the tank until the pressure inside the tank reaches to 250 kPa at which point the valve is closed. Assume that the air behaves as a perfect gas with constant properties (cp = 1.005 kJ/kgK, cv= 0.718 kJ/kgK, R = 0.287 kJ/kgK) . Final temperature of the air inside the tank is ___________ K (round off to one decimal place).
Correct answer is '560'. Can you explain this answer?
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A rigid insulated tank is initially evacuated. It is connected through...
Given : Initially evacuated tank rigid and insulated.
Using unsteady flow energy equation :
Using unsteady flow energy equation :
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A rigid insulated tank is initially evacuated. It is connected through...
Given data:
- Initial pressure of the tank (P1) = 0 kPa (vacuum)
- Pressure of the supply line (P2) = 250 kPa
- Temperature of the supply line (T2) = 400 K
- Specific heat at constant pressure (cp) = 1.005 kJ/kgK
- Specific heat at constant volume (cv) = 0.718 kJ/kgK
- Gas constant (R) = 0.287 kJ/kgK
Assumptions:
- The air inside the tank behaves as a perfect gas with constant properties.
- The process is isochoric (constant volume) during the filling of the tank.
Calculations:
1. Find the initial temperature of the air inside the tank:
- Since the tank is initially evacuated, the pressure inside the tank (P1) is 0 kPa.
- Using the ideal gas equation, P1V1/T1 = P2V2/T2, where V1 and V2 are the initial and final volumes of the tank.
- Since the tank is initially evacuated, V1 = 0.
- Thus, the equation becomes 0/0 = P2V2/T2.
- Rearranging the equation, T1 = T2 * (P1/P2) = 400 * (0/250) = 0 K.
2. Find the final temperature of the air inside the tank:
- The final pressure of the air inside the tank is the same as the pressure in the supply line, which is 250 kPa (P2).
- Since the process is isochoric, the final temperature (Tf) can be determined using the equation P1/T1 = P2/Tf.
- Substituting the known values, 0/0 = 250/Tf.
- Rearranging the equation, Tf = 0.
Explanation:
The final temperature of the air inside the tank is 0 K. This implies that the air inside the tank has lost all its energy and has cooled down to absolute zero. However, this scenario is not physically possible as it violates the laws of thermodynamics. Therefore, the correct answer cannot be 0 K.
It is likely that there is an error in the question or the answer provided. Without additional information or clarification, it is not possible to determine the correct final temperature of the air inside the tank.
- Initial pressure of the tank (P1) = 0 kPa (vacuum)
- Pressure of the supply line (P2) = 250 kPa
- Temperature of the supply line (T2) = 400 K
- Specific heat at constant pressure (cp) = 1.005 kJ/kgK
- Specific heat at constant volume (cv) = 0.718 kJ/kgK
- Gas constant (R) = 0.287 kJ/kgK
Assumptions:
- The air inside the tank behaves as a perfect gas with constant properties.
- The process is isochoric (constant volume) during the filling of the tank.
Calculations:
1. Find the initial temperature of the air inside the tank:
- Since the tank is initially evacuated, the pressure inside the tank (P1) is 0 kPa.
- Using the ideal gas equation, P1V1/T1 = P2V2/T2, where V1 and V2 are the initial and final volumes of the tank.
- Since the tank is initially evacuated, V1 = 0.
- Thus, the equation becomes 0/0 = P2V2/T2.
- Rearranging the equation, T1 = T2 * (P1/P2) = 400 * (0/250) = 0 K.
2. Find the final temperature of the air inside the tank:
- The final pressure of the air inside the tank is the same as the pressure in the supply line, which is 250 kPa (P2).
- Since the process is isochoric, the final temperature (Tf) can be determined using the equation P1/T1 = P2/Tf.
- Substituting the known values, 0/0 = 250/Tf.
- Rearranging the equation, Tf = 0.
Explanation:
The final temperature of the air inside the tank is 0 K. This implies that the air inside the tank has lost all its energy and has cooled down to absolute zero. However, this scenario is not physically possible as it violates the laws of thermodynamics. Therefore, the correct answer cannot be 0 K.
It is likely that there is an error in the question or the answer provided. Without additional information or clarification, it is not possible to determine the correct final temperature of the air inside the tank.
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A rigid insulated tank is initially evacuated. It is connected through a valve to supply line that carries air at a constant pressure and temperature of 250 kPa and 400 K respectively. Now the valve is opened and air is allowed to flow into the tank until the pressure inside the tank reaches to 250 kPa at which point the valve is closed. Assume that the air behaves as a perfect gas with constant properties (cp = 1.005 kJ/kgK, cv= 0.718 kJ/kgK, R = 0.287 kJ/kgK) . Final temperature of the air inside the tank is ___________ K (round off to one decimal place).Correct answer is '560'. Can you explain this answer?
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A rigid insulated tank is initially evacuated. It is connected through a valve to supply line that carries air at a constant pressure and temperature of 250 kPa and 400 K respectively. Now the valve is opened and air is allowed to flow into the tank until the pressure inside the tank reaches to 250 kPa at which point the valve is closed. Assume that the air behaves as a perfect gas with constant properties (cp = 1.005 kJ/kgK, cv= 0.718 kJ/kgK, R = 0.287 kJ/kgK) . Final temperature of the air inside the tank is ___________ K (round off to one decimal place).Correct answer is '560'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A rigid insulated tank is initially evacuated. It is connected through a valve to supply line that carries air at a constant pressure and temperature of 250 kPa and 400 K respectively. Now the valve is opened and air is allowed to flow into the tank until the pressure inside the tank reaches to 250 kPa at which point the valve is closed. Assume that the air behaves as a perfect gas with constant properties (cp = 1.005 kJ/kgK, cv= 0.718 kJ/kgK, R = 0.287 kJ/kgK) . Final temperature of the air inside the tank is ___________ K (round off to one decimal place).Correct answer is '560'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rigid insulated tank is initially evacuated. It is connected through a valve to supply line that carries air at a constant pressure and temperature of 250 kPa and 400 K respectively. Now the valve is opened and air is allowed to flow into the tank until the pressure inside the tank reaches to 250 kPa at which point the valve is closed. Assume that the air behaves as a perfect gas with constant properties (cp = 1.005 kJ/kgK, cv= 0.718 kJ/kgK, R = 0.287 kJ/kgK) . Final temperature of the air inside the tank is ___________ K (round off to one decimal place).Correct answer is '560'. Can you explain this answer?.
A rigid insulated tank is initially evacuated. It is connected through a valve to supply line that carries air at a constant pressure and temperature of 250 kPa and 400 K respectively. Now the valve is opened and air is allowed to flow into the tank until the pressure inside the tank reaches to 250 kPa at which point the valve is closed. Assume that the air behaves as a perfect gas with constant properties (cp = 1.005 kJ/kgK, cv= 0.718 kJ/kgK, R = 0.287 kJ/kgK) . Final temperature of the air inside the tank is ___________ K (round off to one decimal place).Correct answer is '560'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A rigid insulated tank is initially evacuated. It is connected through a valve to supply line that carries air at a constant pressure and temperature of 250 kPa and 400 K respectively. Now the valve is opened and air is allowed to flow into the tank until the pressure inside the tank reaches to 250 kPa at which point the valve is closed. Assume that the air behaves as a perfect gas with constant properties (cp = 1.005 kJ/kgK, cv= 0.718 kJ/kgK, R = 0.287 kJ/kgK) . Final temperature of the air inside the tank is ___________ K (round off to one decimal place).Correct answer is '560'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rigid insulated tank is initially evacuated. It is connected through a valve to supply line that carries air at a constant pressure and temperature of 250 kPa and 400 K respectively. Now the valve is opened and air is allowed to flow into the tank until the pressure inside the tank reaches to 250 kPa at which point the valve is closed. Assume that the air behaves as a perfect gas with constant properties (cp = 1.005 kJ/kgK, cv= 0.718 kJ/kgK, R = 0.287 kJ/kgK) . Final temperature of the air inside the tank is ___________ K (round off to one decimal place).Correct answer is '560'. Can you explain this answer?.
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ample number of questions to practice A rigid insulated tank is initially evacuated. It is connected through a valve to supply line that carries air at a constant pressure and temperature of 250 kPa and 400 K respectively. Now the valve is opened and air is allowed to flow into the tank until the pressure inside the tank reaches to 250 kPa at which point the valve is closed. Assume that the air behaves as a perfect gas with constant properties (cp = 1.005 kJ/kgK, cv= 0.718 kJ/kgK, R = 0.287 kJ/kgK) . Final temperature of the air inside the tank is ___________ K (round off to one decimal place).Correct answer is '560'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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