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A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μA and the collector current changes by 1.5 mA. The load resistance is 5 kΩ. The voltage gain of the transistor will be ___.(In Integers)
Correct answer is '750'. Can you explain this answer?
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A transistor is used in common-emitter mode in an amplifier circuit. W...
ΜA. If the collector current is 2 mA without the signal, what is the voltage gain of the amplifier?
We can use the formula for voltage gain in a common-emitter amplifier:
Av = -Rc / (Rb / β)
where Rc is the collector resistor, Rb is the base resistor, and β is the transistor's current gain.
To find β, we can use the formula:
β = Ic / Ib
where Ic is the collector current and Ib is the base current.
Without the signal, Ic = 2 mA and Ib = Ic / β. We don't know β yet, so let's assume a value of 100 for now:
Ib = 2 mA / 100 = 20 μA
Now, with the signal, Ib changes by 10 μA, so the new value of Ib is:
Ib = 20 μA + 10 μA = 30 μA
Using the same formula, we can find the new value of Ic:
Ic = β * Ib = 100 * 30 μA = 3 mA
The change in collector current is:
ΔIc = Ic - 2 mA = 1 mA
Now we can use the voltage gain formula:
Av = -Rc / (Rb / β) = -Rc * β / Rb
We know β = 100 and ΔIc = 1 mA, so we can find Rc:
ΔV = ΔIc * Rc
10 mV = 1 mA * Rc
Rc = 10 Ω
Now we can find the voltage gain:
Av = -Rc * β / Rb = -10 Ω * 100 / Rb
We don't know Rb yet, but we can use the fact that the base voltage changed by 10 mV to find it:
ΔVb = Ib * Rb
10 mV = 30 μA * Rb
Rb = 333.33 Ω
Finally, we can plug in the values for Rc and Rb to find the voltage gain:
Av = -10 Ω * 100 / 333.33 Ω = -3
The negative sign indicates that the output voltage is inverted relative to the input voltage. Therefore, the voltage gain is 3 (in magnitude) and the output voltage is 3 times larger than the input voltage, but with opposite polarity.
We can use the formula for voltage gain in a common-emitter amplifier:
Av = -Rc / (Rb / β)
where Rc is the collector resistor, Rb is the base resistor, and β is the transistor's current gain.
To find β, we can use the formula:
β = Ic / Ib
where Ic is the collector current and Ib is the base current.
Without the signal, Ic = 2 mA and Ib = Ic / β. We don't know β yet, so let's assume a value of 100 for now:
Ib = 2 mA / 100 = 20 μA
Now, with the signal, Ib changes by 10 μA, so the new value of Ib is:
Ib = 20 μA + 10 μA = 30 μA
Using the same formula, we can find the new value of Ic:
Ic = β * Ib = 100 * 30 μA = 3 mA
The change in collector current is:
ΔIc = Ic - 2 mA = 1 mA
Now we can use the voltage gain formula:
Av = -Rc / (Rb / β) = -Rc * β / Rb
We know β = 100 and ΔIc = 1 mA, so we can find Rc:
ΔV = ΔIc * Rc
10 mV = 1 mA * Rc
Rc = 10 Ω
Now we can find the voltage gain:
Av = -Rc * β / Rb = -10 Ω * 100 / Rb
We don't know Rb yet, but we can use the fact that the base voltage changed by 10 mV to find it:
ΔVb = Ib * Rb
10 mV = 30 μA * Rb
Rb = 333.33 Ω
Finally, we can plug in the values for Rc and Rb to find the voltage gain:
Av = -10 Ω * 100 / 333.33 Ω = -3
The negative sign indicates that the output voltage is inverted relative to the input voltage. Therefore, the voltage gain is 3 (in magnitude) and the output voltage is 3 times larger than the input voltage, but with opposite polarity.
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A transistor is used in common-emitter mode in an amplifier circuit. W...
= 103 Ω
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A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μA and the collector current changes by 1.5 mA. The load resistance is 5 kΩ. The voltage gain of the transistor will be ___.(In Integers)Correct answer is '750'. Can you explain this answer?
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A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μA and the collector current changes by 1.5 mA. The load resistance is 5 kΩ. The voltage gain of the transistor will be ___.(In Integers)Correct answer is '750'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μA and the collector current changes by 1.5 mA. The load resistance is 5 kΩ. The voltage gain of the transistor will be ___.(In Integers)Correct answer is '750'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μA and the collector current changes by 1.5 mA. The load resistance is 5 kΩ. The voltage gain of the transistor will be ___.(In Integers)Correct answer is '750'. Can you explain this answer?.
A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μA and the collector current changes by 1.5 mA. The load resistance is 5 kΩ. The voltage gain of the transistor will be ___.(In Integers)Correct answer is '750'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μA and the collector current changes by 1.5 mA. The load resistance is 5 kΩ. The voltage gain of the transistor will be ___.(In Integers)Correct answer is '750'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μA and the collector current changes by 1.5 mA. The load resistance is 5 kΩ. The voltage gain of the transistor will be ___.(In Integers)Correct answer is '750'. Can you explain this answer?.
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