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The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL-1 is _______. (Molar mass of glucose = 180 g mol-1, R = 0.083 L bar K-1 mol-1) (Nearest integer)
Correct answer is '54'. Can you explain this answer?
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The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose ...
Given:
Osmotic pressure of blood = 7.47 bar
Temperature (T) = 300 K
Molar mass of glucose (M) = 180 g/mol
Gas constant (R) = 0.083 L bar K^-1mol^-1
To find:
Concentration of glucose solution (C)
Formula used:
π = CRT
where,
π = Osmotic pressure
C = Concentration
R = Gas constant
T = Temperature
Calculation:
π = CRT
C = π/(RT)
C = 7.47/(0.083 x 300)
C = 7.47/24.9
C = 0.299 g/mL
But the concentration is asked in g/L.
Therefore, we need to convert g/mL to g/L.
1 mL = 1/1000 L
C = 0.299 x 1000
C = 299 g/L
Now, we need to find the concentration in g/L of glucose solution.
Glucose molecular weight = 180 g/mol
So, we need to find the concentration in terms of moles.
Concentration in moles = Concentration in g/L / Molecular weight
Concentration in moles = 299/180
Concentration in moles = 1.66 mol/L
Therefore, the concentration of glucose solution in g/L is 54 (approximately).
Answer: 54.
Osmotic pressure of blood = 7.47 bar
Temperature (T) = 300 K
Molar mass of glucose (M) = 180 g/mol
Gas constant (R) = 0.083 L bar K^-1mol^-1
To find:
Concentration of glucose solution (C)
Formula used:
π = CRT
where,
π = Osmotic pressure
C = Concentration
R = Gas constant
T = Temperature
Calculation:
π = CRT
C = π/(RT)
C = 7.47/(0.083 x 300)
C = 7.47/24.9
C = 0.299 g/mL
But the concentration is asked in g/L.
Therefore, we need to convert g/mL to g/L.
1 mL = 1/1000 L
C = 0.299 x 1000
C = 299 g/L
Now, we need to find the concentration in g/L of glucose solution.
Glucose molecular weight = 180 g/mol
So, we need to find the concentration in terms of moles.
Concentration in moles = Concentration in g/L / Molecular weight
Concentration in moles = 299/180
Concentration in moles = 1.66 mol/L
Therefore, the concentration of glucose solution in g/L is 54 (approximately).
Answer: 54.
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Community Answer
The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose ...
7.47 = C × 0.083 × 300
(π = CRT)
(Where C represents the concentration of glucose solution and π represents osmotic pressure)
= 54 gm/l
(π = CRT)
(Where C represents the concentration of glucose solution and π represents osmotic pressure)
= 54 gm/l
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The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL-1is _______. (Molar mass of glucose = 180 g mol-1,R = 0.083 L bar K-1mol-1) (Nearest integer)Correct answer is '54'. Can you explain this answer?
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The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL-1is _______. (Molar mass of glucose = 180 g mol-1,R = 0.083 L bar K-1mol-1) (Nearest integer)Correct answer is '54'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL-1is _______. (Molar mass of glucose = 180 g mol-1,R = 0.083 L bar K-1mol-1) (Nearest integer)Correct answer is '54'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL-1is _______. (Molar mass of glucose = 180 g mol-1,R = 0.083 L bar K-1mol-1) (Nearest integer)Correct answer is '54'. Can you explain this answer?.
The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL-1is _______. (Molar mass of glucose = 180 g mol-1,R = 0.083 L bar K-1mol-1) (Nearest integer)Correct answer is '54'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL-1is _______. (Molar mass of glucose = 180 g mol-1,R = 0.083 L bar K-1mol-1) (Nearest integer)Correct answer is '54'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL-1is _______. (Molar mass of glucose = 180 g mol-1,R = 0.083 L bar K-1mol-1) (Nearest integer)Correct answer is '54'. Can you explain this answer?.
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