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For a series LCR circuit with R = 100 Ω, L = 0.5 mH, C = 0.1 pF connected across 220 V-50 Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit is
  • a)
    ≈ 90°, predominantly inductive circuit
  • b)
    0°, resistive circuit
  • c)
    0°, resonance circuit
  • d)
    ≈ 90°, predominantly capacitive circuit
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
For a series LCR circuit with R = 100 Ω, L = 0.5 mH, C = 0.1 pF ...


Analysis of the Series LCR Circuit:

The given series LCR circuit consists of a resistor (R = 100 Ω), an inductor (L = 0.5 mH), and a capacitor (C = 0.1 pF) connected across a 220 V-50 Hz AC supply.

Phase Angle and Nature of the Circuit:
- The phase angle between current and supplied voltage in a series LCR circuit is given by the formula:
tanΦ = (XL - XC) / R
where XL is the inductive reactance, XC is the capacitive reactance, and R is the resistance.

- In this case, XL = 2πfL = 2π * 50 * 0.5 x 10^-3 = 0.157 Ω
XC = 1 / 2πfC = 1 / (2π * 50 * 0.1 x 10^-12) = 31830 Ω

- Therefore, tanΦ = (0.157 - 31830) / 100 = -31829.843
Φ = -89.995°

- The phase angle is approximately -90°, indicating that the circuit is predominantly capacitive.

- The nature of the circuit is predominantly capacitive since the capacitive reactance (XC) is much larger than the inductive reactance (XL) in this case.

Therefore, the correct answer is option 'D': ≈ 90°, predominantly capacitive circuit.
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Community Answer
For a series LCR circuit with R = 100 Ω, L = 0.5 mH, C = 0.1 pF ...
R = 100Ω
XL = ωL = 50π × 10-3 

XC >> XL
And |XC - XL| >> R
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For a series LCR circuit with R = 100 Ω, L = 0.5 mH, C = 0.1 pF connected across 220 V-50 Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit isa)≈ 90°, predominantly inductive circuitb)0°, resistive circuitc)0°, resonance circuitd)≈ 90°, predominantly capacitive circuitCorrect answer is option 'D'. Can you explain this answer?
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For a series LCR circuit with R = 100 Ω, L = 0.5 mH, C = 0.1 pF connected across 220 V-50 Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit isa)≈ 90°, predominantly inductive circuitb)0°, resistive circuitc)0°, resonance circuitd)≈ 90°, predominantly capacitive circuitCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For a series LCR circuit with R = 100 Ω, L = 0.5 mH, C = 0.1 pF connected across 220 V-50 Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit isa)≈ 90°, predominantly inductive circuitb)0°, resistive circuitc)0°, resonance circuitd)≈ 90°, predominantly capacitive circuitCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a series LCR circuit with R = 100 Ω, L = 0.5 mH, C = 0.1 pF connected across 220 V-50 Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit isa)≈ 90°, predominantly inductive circuitb)0°, resistive circuitc)0°, resonance circuitd)≈ 90°, predominantly capacitive circuitCorrect answer is option 'D'. Can you explain this answer?.
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