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A slotted ALOHA network transmits 200-bit frames using a shared channel with a 200 Kbps bandwidth. Find the throughput of the system, if the system (all stations put together) produces 250 frames per second:
- a)49
- b)368
- c)149
- d)151
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A slotted ALOHA network transmits 200-bit frames using a shared channe...
Slotted ALOHA Network:
Slotted ALOHA is a protocol in which a station can transmit only at the beginning of a time slot. It is an algorithm for multiple access transmission.
Given Data:
Frame size = 200 bits
Bandwidth = 200 Kbps
Number of frames transmitted per second = 250
Calculation:
The throughput of the system can be calculated as follows:
1. Total possible data that can be transmitted per second:
Data transmitted = Bandwidth × Time
= 200 Kbps × 1 second
= 200,000 bits
2. Total data that can be transmitted per second considering Slotted ALOHA:
Let the efficiency of the system be 'e'.
The maximum efficiency of Slotted ALOHA is 1/e = 1/e^2.
Therefore, e^2 = Data transmitted / Total data produced
= (200,000 × 250) / (200) bits
e^2 = 250
e = 15.81%
3. Throughput of the system:
Throughput = e × Data transmitted
= 15.81% × 200,000 bits
= 31,620 bits/second or 31.62 Kbps
Answer:
The throughput of the system is 31.62 Kbps, which is closest to option 'A' (49).
Slotted ALOHA is a protocol in which a station can transmit only at the beginning of a time slot. It is an algorithm for multiple access transmission.
Given Data:
Frame size = 200 bits
Bandwidth = 200 Kbps
Number of frames transmitted per second = 250
Calculation:
The throughput of the system can be calculated as follows:
1. Total possible data that can be transmitted per second:
Data transmitted = Bandwidth × Time
= 200 Kbps × 1 second
= 200,000 bits
2. Total data that can be transmitted per second considering Slotted ALOHA:
Let the efficiency of the system be 'e'.
The maximum efficiency of Slotted ALOHA is 1/e = 1/e^2.
Therefore, e^2 = Data transmitted / Total data produced
= (200,000 × 250) / (200) bits
e^2 = 250
e = 15.81%
3. Throughput of the system:
Throughput = e × Data transmitted
= 15.81% × 200,000 bits
= 31,620 bits/second or 31.62 Kbps
Answer:
The throughput of the system is 31.62 Kbps, which is closest to option 'A' (49).
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Community Answer
A slotted ALOHA network transmits 200-bit frames using a shared channe...
In slotted aloha, there are time slots for the stations to transmit the data. Stations can transmit data in time slots. Stations have to wait for their time slots to transmit the data.
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