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An aqueous solution of NiCl2 was heated with excess sodium cyanide in presence of strong oxidizing agent to form [Ni (CN)6]2-. The total change in number of unpaired electrons on metal centre is _________.
Correct answer is '2'. Can you explain this answer?
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An aqueous solution of NiCl2 was heated with excess sodium cyanide in ...
Introduction:
In the given question, an aqueous solution of NiCl2 is heated with excess sodium cyanide in the presence of a strong oxidizing agent. The resulting complex is [Ni(CN)6]2-. We need to determine the total change in the number of unpaired electrons on the metal center.
Explanation:
To understand the change in the number of unpaired electrons, let's analyze the electronic configuration of nickel (Ni) and the [Ni(CN)6]2- complex.
Electronic configuration of Nickel (Ni):
The atomic number of nickel is 28, which means it has 28 electrons. The electronic configuration of nickel is 1s2 2s2 2p6 3s2 3p6 4s2 3d8. In the 3d subshell, there are 8 electrons, out of which 2 are unpaired.
Formation of [Ni(CN)6]2- complex:
When NiCl2 reacts with sodium cyanide (NaCN) in the presence of a strong oxidizing agent, the cyanide ions (CN-) coordinate with the nickel ion (Ni2+) to form a complex.
The coordination number of nickel in the [Ni(CN)6]2- complex is 6, which means it is surrounded by six ligands (cyanide ions). Each ligand donates one pair of electrons to form a coordinate bond with the metal center.
Change in the number of unpaired electrons:
In the [Ni(CN)6]2- complex, the nickel ion (Ni2+) undergoes hybridization to form six sigma bonds with the cyanide ions. The d-orbitals of the nickel ion participate in hybridization, resulting in the formation of six new hybrid orbitals.
Explanation of hybridization:
The 3d orbitals of the nickel ion combine with the 4s and 4p orbitals to form six sp3d2 hybrid orbitals. These hybrid orbitals are directed towards the six ligands (cyanide ions) in an octahedral arrangement.
In the process of hybridization, the two unpaired electrons of nickel (3d8) get paired up, resulting in the formation of the [Ni(CN)6]2- complex with 2 paired electrons.
Conclusion:
Therefore, the total change in the number of unpaired electrons on the metal center (nickel) is 2.
In the given question, an aqueous solution of NiCl2 is heated with excess sodium cyanide in the presence of a strong oxidizing agent. The resulting complex is [Ni(CN)6]2-. We need to determine the total change in the number of unpaired electrons on the metal center.
Explanation:
To understand the change in the number of unpaired electrons, let's analyze the electronic configuration of nickel (Ni) and the [Ni(CN)6]2- complex.
Electronic configuration of Nickel (Ni):
The atomic number of nickel is 28, which means it has 28 electrons. The electronic configuration of nickel is 1s2 2s2 2p6 3s2 3p6 4s2 3d8. In the 3d subshell, there are 8 electrons, out of which 2 are unpaired.
Formation of [Ni(CN)6]2- complex:
When NiCl2 reacts with sodium cyanide (NaCN) in the presence of a strong oxidizing agent, the cyanide ions (CN-) coordinate with the nickel ion (Ni2+) to form a complex.
The coordination number of nickel in the [Ni(CN)6]2- complex is 6, which means it is surrounded by six ligands (cyanide ions). Each ligand donates one pair of electrons to form a coordinate bond with the metal center.
Change in the number of unpaired electrons:
In the [Ni(CN)6]2- complex, the nickel ion (Ni2+) undergoes hybridization to form six sigma bonds with the cyanide ions. The d-orbitals of the nickel ion participate in hybridization, resulting in the formation of six new hybrid orbitals.
Explanation of hybridization:
The 3d orbitals of the nickel ion combine with the 4s and 4p orbitals to form six sp3d2 hybrid orbitals. These hybrid orbitals are directed towards the six ligands (cyanide ions) in an octahedral arrangement.
In the process of hybridization, the two unpaired electrons of nickel (3d8) get paired up, resulting in the formation of the [Ni(CN)6]2- complex with 2 paired electrons.
Conclusion:
Therefore, the total change in the number of unpaired electrons on the metal center (nickel) is 2.
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An aqueous solution of NiCl2 was heated with excess sodium cyanide in ...
Pairing will be there zero unpaired electron
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An aqueous solution of NiCl2 was heated with excess sodium cyanide in presence of strong oxidizing agent to form [Ni (CN)6]2-. The total change in number of unpaired electrons on metal centre is _________.Correct answer is '2'. Can you explain this answer?
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