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The radiation corresponding to 3 → 2 transition of a hydrogen atom falls on a gold surface to generate photoelectrons. These electrons are passed through a magnetic field of 5 × 10-4 T. Assume that the radius of the largest circular path followed by these electrons is 7 mm, the work function of the metal is:
(Mass of electron = 9.1 × 10-31 kg)
  • a)
    0.82 eV
  • b)
    0.16 eV
  • c)
    1.88 eV
  • d)
    1.36 eV
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The radiation corresponding to 3 → 2 transition of a hydrogen ato...

3 → 2 ⇒ 1.89 eV
B = 5 × 10-4 T
r = 7 mm

= 1.077 eV
We know, work function = energy incident - (KE)electron
ϕ = 1.89 - 1.077 = 0.813 eV
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The radiation corresponding to 3 → 2 transition of a hydrogen atom falls on a gold surface to generate photoelectrons. These electrons are passed through a magnetic field of 5 × 10-4 T. Assume that the radius of the largest circular path followed by these electrons is 7 mm, the work function of the metal is:(Mass of electron = 9.1 × 10-31 kg)a)0.82 eVb)0.16 eVc)1.88 eVd)1.36 eVCorrect answer is option 'A'. Can you explain this answer?
Question Description
The radiation corresponding to 3 → 2 transition of a hydrogen atom falls on a gold surface to generate photoelectrons. These electrons are passed through a magnetic field of 5 × 10-4 T. Assume that the radius of the largest circular path followed by these electrons is 7 mm, the work function of the metal is:(Mass of electron = 9.1 × 10-31 kg)a)0.82 eVb)0.16 eVc)1.88 eVd)1.36 eVCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The radiation corresponding to 3 → 2 transition of a hydrogen atom falls on a gold surface to generate photoelectrons. These electrons are passed through a magnetic field of 5 × 10-4 T. Assume that the radius of the largest circular path followed by these electrons is 7 mm, the work function of the metal is:(Mass of electron = 9.1 × 10-31 kg)a)0.82 eVb)0.16 eVc)1.88 eVd)1.36 eVCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The radiation corresponding to 3 → 2 transition of a hydrogen atom falls on a gold surface to generate photoelectrons. These electrons are passed through a magnetic field of 5 × 10-4 T. Assume that the radius of the largest circular path followed by these electrons is 7 mm, the work function of the metal is:(Mass of electron = 9.1 × 10-31 kg)a)0.82 eVb)0.16 eVc)1.88 eVd)1.36 eVCorrect answer is option 'A'. Can you explain this answer?.
Solutions for The radiation corresponding to 3 → 2 transition of a hydrogen atom falls on a gold surface to generate photoelectrons. These electrons are passed through a magnetic field of 5 × 10-4 T. Assume that the radius of the largest circular path followed by these electrons is 7 mm, the work function of the metal is:(Mass of electron = 9.1 × 10-31 kg)a)0.82 eVb)0.16 eVc)1.88 eVd)1.36 eVCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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