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Following is an incorrect pseudocode for the algorithm which is supposed to determine whether a sequence of parentheses is balanced:
declare a character stack
while ( more input is available)
{
read a character
if ( the character is a '(' )
push it on the stack
else if ( the character is a ')' and the stack is not empty )
pop a character off the stack
else
print "unbalanced" and exit
}
print "balanced"
while ( more input is available)
{
read a character
if ( the character is a '(' )
push it on the stack
else if ( the character is a ')' and the stack is not empty )
pop a character off the stack
else
print "unbalanced" and exit
}
print "balanced"
Which of these unbalanced sequences does the above code think is balanced?
- a)((())
- b)())(()
- c)(()()))
- d)(()))()
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Following is an incorrect pseudocode for the algorithm which is suppos...
At the end of while loop, we must check whether the stack is empty or not. For input ((()), the stack doesn’t remain empty after the loop.
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Community Answer
Following is an incorrect pseudocode for the algorithm which is suppos...
"Unbalanced parentheses"
To fix the pseudocode, the correct approach to determine whether a sequence of parentheses is balanced is as follows:
1. Declare a character stack.
2. Read the input character by character.
3. If the character is an opening parenthesis (i.e., '('), push it onto the stack.
4. If the character is a closing parenthesis (i.e., ')'), check if the stack is empty.
- If the stack is empty, print "Unbalanced parentheses" and exit.
- If the stack is not empty, pop the top character from the stack.
5. After all characters have been processed, check if the stack is empty.
- If the stack is empty, print "Balanced parentheses".
- If the stack is not empty, print "Unbalanced parentheses".
Here is the corrected pseudocode:
```
declare a character stack
while (more input is available){
read a character
if (the character is an opening parenthesis){
push it onto the stack
}
else if (the character is a closing parenthesis){
if (the stack is empty){
print "Unbalanced parentheses" and exit
}
else{
pop a character from the stack
}
}
}
if (the stack is empty){
print "Balanced parentheses"
}
else{
print "Unbalanced parentheses"
}
```
To fix the pseudocode, the correct approach to determine whether a sequence of parentheses is balanced is as follows:
1. Declare a character stack.
2. Read the input character by character.
3. If the character is an opening parenthesis (i.e., '('), push it onto the stack.
4. If the character is a closing parenthesis (i.e., ')'), check if the stack is empty.
- If the stack is empty, print "Unbalanced parentheses" and exit.
- If the stack is not empty, pop the top character from the stack.
5. After all characters have been processed, check if the stack is empty.
- If the stack is empty, print "Balanced parentheses".
- If the stack is not empty, print "Unbalanced parentheses".
Here is the corrected pseudocode:
```
declare a character stack
while (more input is available){
read a character
if (the character is an opening parenthesis){
push it onto the stack
}
else if (the character is a closing parenthesis){
if (the stack is empty){
print "Unbalanced parentheses" and exit
}
else{
pop a character from the stack
}
}
}
if (the stack is empty){
print "Balanced parentheses"
}
else{
print "Unbalanced parentheses"
}
```
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Following is an incorrect pseudocode for the algorithm which is supposed to determine whether a sequence of parentheses is balanced:declare a character stackwhile ( more input is available){ read a character if ( the character is a ( ) push it on the stack else if ( the character is a ) and the stack is not empty ) pop a character off the stack else print "unbalanced" and exit}print "balanced"Which of these unbalanced sequences does the above code think is balanced?a)((())b)())(()c)(()()))d)(()))()Correct answer is option 'A'. Can you explain this answer?
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