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The schematic shown below generates FM signal as a wideband frequency modulator using the indirect method. The output FM signal is characterized by fc = 100 MHz, Δf = 75 kHz (min).
If the phase modulator has a modulation index of β = 0.3 radians, then the values of n1, n2 will be respectively
  • a)
    25, 50
  • b)
    75, 50
  • c)
    50, 25
  • d)
    50, 75
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The schematic shown below generates FM signal as a wideband frequency...
The lowest modulation frequency i.e., tx = 100 Hz
Produces a frequency deviation f1 = β x fme = (0.2 100) = 20 Hz
The highest modulation frequency i.e. fm = 15 kHz
Produces a frequency deviation = Δf1 = β x fmh = (0.2 x 15) = 3 kHz
Let us take the case of 100 H(fmi) as the worst case.
n1n2 = Δf/Δf1 = 75000/20 = 3750… (i)
And f1 - n1f1 = fc/n2
Hence, with f1 = 0.1 MHz, f2 = 9.5 MHz, fc = 100 MHz
We have, 9.5 – 0.1 n1 = 100/n2 … (ii)
Solving (i) and (ii), we get
n1 = 75, n2 = 50
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The schematic shown below generates FM signal as a wideband frequency modulator using the indirect method. The output FM signal is characterized by fc = 100 MHz, Δf = 75 kHz (min).If the phase modulator has a modulation index of β = 0.3 radians, then the values of n1, n2 will be respectivelya)25, 50b)75, 50c)50, 25d)50, 75Correct answer is option 'B'. Can you explain this answer?
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