Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > The seven elements A, B, C, D, E, F and G are...
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The seven elements A, B, C, D, E, F and G are pushed onto a stack in reverse order, i.e., starting from G. The stack is popped five times and each element is inserted into a queue.Two elements are deleted from the queue and pushed back onto the stack. Now, one element is popped from the stack. The popped item is ________.
- a)A
- b)B
- c)F
- d)G
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
The seven elements A, B, C, D, E, F and G are pushed onto a stack in r...
Explanation:
The given problem involves using a stack and a queue to manipulate a set of elements. Let's break down the steps to understand the solution.
Step 1: Pushing elements onto the stack
The seven elements A, B, C, D, E, F, and G are pushed onto the stack in reverse order, starting from G. This means G is pushed first, followed by F, E, D, C, B, and A.
Step 2: Popping elements from the stack and inserting into the queue
The stack is popped five times, and each popped element is inserted into a queue. This means that the elements are transferred from the stack to the queue in the order they were pushed onto the stack, i.e., A, B, C, D, and E.
Step 3: Deleting two elements from the queue and pushing back onto the stack
Two elements are deleted from the queue. Since the elements were transferred from the stack to the queue in the same order, the first two elements in the queue would be A and B. These elements are then pushed back onto the stack, so the stack now contains A and B at the top, followed by F, G, E, D, and C.
Step 4: Popping one element from the stack
Now, one element is popped from the stack. Since the last two elements pushed onto the stack were A and B, and the stack follows the Last-In-First-Out (LIFO) principle, the element popped from the stack would be B. Therefore, the correct answer is option 'B'.
In summary, the correct answer is option 'B' because after pushing and popping elements onto the stack and transferring them to a queue, the last two elements pushed back onto the stack were A and B, and the element popped from the stack would be the topmost element, which is B.
The given problem involves using a stack and a queue to manipulate a set of elements. Let's break down the steps to understand the solution.
Step 1: Pushing elements onto the stack
The seven elements A, B, C, D, E, F, and G are pushed onto the stack in reverse order, starting from G. This means G is pushed first, followed by F, E, D, C, B, and A.
Step 2: Popping elements from the stack and inserting into the queue
The stack is popped five times, and each popped element is inserted into a queue. This means that the elements are transferred from the stack to the queue in the order they were pushed onto the stack, i.e., A, B, C, D, and E.
Step 3: Deleting two elements from the queue and pushing back onto the stack
Two elements are deleted from the queue. Since the elements were transferred from the stack to the queue in the same order, the first two elements in the queue would be A and B. These elements are then pushed back onto the stack, so the stack now contains A and B at the top, followed by F, G, E, D, and C.
Step 4: Popping one element from the stack
Now, one element is popped from the stack. Since the last two elements pushed onto the stack were A and B, and the stack follows the Last-In-First-Out (LIFO) principle, the element popped from the stack would be B. Therefore, the correct answer is option 'B'.
In summary, the correct answer is option 'B' because after pushing and popping elements onto the stack and transferring them to a queue, the last two elements pushed back onto the stack were A and B, and the element popped from the stack would be the topmost element, which is B.
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Community Answer
The seven elements A, B, C, D, E, F and G are pushed onto a stack in r...
In fig:-1 elements are inserted into a stack then in fig:-2 top 5 elements are popped and these 5 elements are inserted into a queue which is shown in fig:-3, now first two elements are deleted from queue and pushed into stack one by one which is shown in fig:-5.
At top of the stack element B is presented.
So, option (B) is correct.
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The seven elements A, B, C, D, E, F and G are pushed onto a stack in reverse order, i.e., starting from G. The stack is popped five times and each element is inserted into a queue.Two elements are deleted from the queue and pushed back onto the stack. Now, one element is popped from the stack. The popped item is ________.a)Ab)Bc)Fd)GCorrect answer is option 'B'. Can you explain this answer?
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