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In a direct current arc welding process, the power source has an open circuit voltage of 100 V and short circuit current of 1000 A. Assume a linear relationship between voltage and current. The arc voltage (V) varies with the arc length (l) as V = 10 + 5l, where V is in volts and l is in mm. The maximum available arc power during the process is _________ kVA (in integer).
    Correct answer is '25'. Can you explain this answer?
    Most Upvoted Answer
    In a direct current arc welding process, the power source has an open ...
    Given Information:
    - Open circuit voltage of the power source = 100 V
    - Short circuit current of the power source = 1000 A
    - Arc voltage varies with arc length as V = 10 + 5l, where V is in volts and l is in mm

    To Find:
    - Maximum available arc power during the process in kVA

    Calculating the Arc Voltage:
    The given relationship between arc voltage (V) and arc length (l) is V = 10 + 5l.
    To calculate the maximum available arc power, we need to find the maximum arc voltage.

    Given that the open circuit voltage of the power source is 100 V, we can set up the following equation:
    100 = 10 + 5l

    Solving for l:
    5l = 100 - 10
    5l = 90
    l = 90/5
    l = 18 mm

    Calculating the Arc Power:
    The power in an electrical circuit can be calculated using the formula: P = VI, where P is power in watts, V is voltage in volts, and I is current in amperes.

    Substituting the values:
    P = 1000 A * (10 + 5 * 18 mm)

    Converting mm to meters:
    P = 1000 A * (10 + 5 * 0.018 m)

    Calculating the power:
    P = 1000 A * (10 + 0.09 m)
    P = 1000 A * 10.09 m
    P = 10090 W

    Converting the power to kilovolt-amperes (kVA):
    1 W = 0.001 kVA
    P(kVA) = 10090 W * 0.001
    P(kVA) = 10.09 kVA

    Conclusion:
    The maximum available arc power during the welding process is 10.09 kVA, which can be approximated to 10 kVA. However, the correct answer provided is 25 kVA, which may be due to a different calculation or assumption made.
    Free Test
    Community Answer
    In a direct current arc welding process, the power source has an open ...
    Given : Open Circuit Voltage (VOC ) = 100V
    Short Circuit Current (ISC) = 1000 A
    Here, V = 10+ 5l
    For maximum power

    So,
    Maximum Power P,

    = 50 x 500
    = 25000 VA
    = 25 kVA
    Hence, the maximum available power during the process is 25 kVA.
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    In a direct current arc welding process, the power source has an open circuit voltage of 100 V and short circuit current of 1000 A. Assume a linear relationship between voltage and current. The arc voltage (V) varies with the arc length (l) as V = 10 + 5l, where V is in volts and l is in mm. The maximum available arc power during the process is _________ kVA (in integer).Correct answer is '25'. Can you explain this answer?
    Question Description
    In a direct current arc welding process, the power source has an open circuit voltage of 100 V and short circuit current of 1000 A. Assume a linear relationship between voltage and current. The arc voltage (V) varies with the arc length (l) as V = 10 + 5l, where V is in volts and l is in mm. The maximum available arc power during the process is _________ kVA (in integer).Correct answer is '25'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a direct current arc welding process, the power source has an open circuit voltage of 100 V and short circuit current of 1000 A. Assume a linear relationship between voltage and current. The arc voltage (V) varies with the arc length (l) as V = 10 + 5l, where V is in volts and l is in mm. The maximum available arc power during the process is _________ kVA (in integer).Correct answer is '25'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a direct current arc welding process, the power source has an open circuit voltage of 100 V and short circuit current of 1000 A. Assume a linear relationship between voltage and current. The arc voltage (V) varies with the arc length (l) as V = 10 + 5l, where V is in volts and l is in mm. The maximum available arc power during the process is _________ kVA (in integer).Correct answer is '25'. Can you explain this answer?.
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