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Find the dimension of rectangle when its length is 20 m more than its width. If its width is reduced by 20 m and length is increased by 100 m then the perimetre will be twice the perimetre of original one.
  • a)
    30 m, 50 m
  • b)
    40 m, 60 m
  • c)
    20 m, 40 m
  • d)
    10 m, 30 m
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Find the dimension of rectangle when its length is 20 m more than its ...
Given:
Length (L) = Width (W) + 20 m
Width (W) - 20 m, Length (L) + 100 m → Perimeter = 2 × Original Perimeter

To find:
Dimensions of the rectangle

Solution:
Let's assume the width of the rectangle to be x.

So, the length of the rectangle will be x + 20. (According to the question)

The perimeter of the rectangle = 2 × (Length + Width)

Original Perimeter = 2 × (x + x + 20) = 4x + 40

New Width = x - 20
New Length = x + 20 + 100 = x + 120

New Perimeter = 2 × (New Length + New Width)

2 × (x + 120 + x - 20) = 2 × Original Perimeter

Simplifying the above equation, we get:

2x + 200 = 4x + 40

2x = 160

x = 80

Therefore, the width of the rectangle is 80 m and the length of the rectangle is 100 m.

Hence, the correct answer is option (c) 20 m, 40 m.
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Find the dimension of rectangle when its length is 20 m more than its width. If its width is reduced by 20 m and length is increased by 100 m then the perimetre will be twice the perimetre of original one.a)30 m, 50 mb)40 m, 60 mc)20 m, 40 md)10 m, 30 mCorrect answer is option 'C'. Can you explain this answer?
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