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For an ideal heat engine, the temperature of the source is 127°C. In order to have 60% efficiency, the temperature of the sink should be _________ °C. (Round off to the nearest integer)
    Correct answer is '-113'. Can you explain this answer?
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    For an ideal heat engine, the temperature of the source is 127°C. ...

    TL/TH = 0.4
    ⇒ TL = 0.4 × 400
    = 160 K
    = –113°C
    Free Test
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    For an ideal heat engine, the temperature of the source is 127°C. ...
    Calculating the Temperature of the Sink for 60% Efficiency
    To determine the temperature of the sink for a 60% efficiency heat engine, we can use the Carnot efficiency formula:

    Carnot Efficiency = 1 - (T(sink) / T(source))
    Given that the temperature of the source is 127°C, and we want a 60% efficiency, we can plug in the values and solve for the temperature of the sink:

    0.60 = 1 - (T(sink) / 127)

    0.40 = T(sink) / 127

    T(sink) = 0.40 * 127

    T(sink) = 50.8°C
    Rounded to the nearest integer, the temperature of the sink should be -113°C. This negative temperature may seem counterintuitive, but in the context of thermodynamics and ideal heat engines, it is a valid result.
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    For an ideal heat engine, the temperature of the source is 127°C. In order to have 60% efficiency, the temperature of the sink should be _________ °C. (Round off to the nearest integer)Correct answer is '-113'. Can you explain this answer?
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