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The inorder and preorder Traversal of binary Tree are dbeafcg and abdecfg respectively. The post-order Traversal is __________.
- a)dbefacg
- b)debfagc
- c)dbefcga
- d)debfgca
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
The inorder and preorder Traversal of binary Tree are dbeafcg and abde...
Explanation:
Given Traversals:
- Inorder: dbeafcg
- Preorder: abdecfg
Steps to Find Post-order Traversal:
- The first element in the Preorder traversal is the root of the tree (a).
- Find the index of the root in the Inorder traversal (index 3).
- The elements to the left of the root in the Inorder traversal represent the left subtree (dbe).
- The elements to the right of the root in the Inorder traversal represent the right subtree (fcg).
- Recursively repeat the above steps for the left and right subtrees.
Post-order Traversal:
- Left Subtree: dbef
- Right Subtree: cg
- Root: a
- Combine the post-order traversals of the left subtree, right subtree, and root to get the final post-order traversal: debfgca
Therefore, the correct post-order Traversal of the binary tree is debfgca.
Given Traversals:
- Inorder: dbeafcg
- Preorder: abdecfg
Steps to Find Post-order Traversal:
- The first element in the Preorder traversal is the root of the tree (a).
- Find the index of the root in the Inorder traversal (index 3).
- The elements to the left of the root in the Inorder traversal represent the left subtree (dbe).
- The elements to the right of the root in the Inorder traversal represent the right subtree (fcg).
- Recursively repeat the above steps for the left and right subtrees.
Post-order Traversal:
- Left Subtree: dbef
- Right Subtree: cg
- Root: a
- Combine the post-order traversals of the left subtree, right subtree, and root to get the final post-order traversal: debfgca
Therefore, the correct post-order Traversal of the binary tree is debfgca.
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Community Answer
The inorder and preorder Traversal of binary Tree are dbeafcg and abde...
Inorder and preorder Traversal of binary Tree are dbeafcg and abdecfg respectively.
From preorder(Parent left right) and inorder ( left parent right) we can easily find post order.
From preorder(a(bdecfg)), it is clear that a is parent node(root node), Now we will look for left subttree in inorder traversal i.e. dbe and fcg.
To find root node and left subtree and right subtree of these subtree we will do the same process as above:
Now see this scenario in graph:
Now from above tree we can easily find out the post order(left right parent):
i.e. debfgca.
So, option (D) is correct.
From preorder(Parent left right) and inorder ( left parent right) we can easily find post order.
From preorder(a(bdecfg)), it is clear that a is parent node(root node), Now we will look for left subttree in inorder traversal i.e. dbe and fcg.
To find root node and left subtree and right subtree of these subtree we will do the same process as above:
Now see this scenario in graph:
Now from above tree we can easily find out the post order(left right parent):
i.e. debfgca.
So, option (D) is correct.
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