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For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 3/4d, where d is the separation between the plates of parallel plate capacitor. The new capacitance (C) in terms of original capacitance (C0) is given by the following relation:a)b)c)d)Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 3/4d, where d is the separation between the plates of parallel plate capacitor. The new capacitance (C) in terms of original capacitance (C0) is given by the following relation:a)b)c)d)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
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For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 3/4d, where d is the separation between the plates of parallel plate capacitor. The new capacitance (C) in terms of original capacitance (C0) is given by the following relation:a)b)c)d)Correct answer is option 'C'. Can you explain this answer?, a detailed solution for For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 3/4d, where d is the separation between the plates of parallel plate capacitor. The new capacitance (C) in terms of original capacitance (C0) is given by the following relation:a)b)c)d)Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 3/4d, where d is the separation between the plates of parallel plate capacitor. The new capacitance (C) in terms of original capacitance (C0) is given by the following relation:a)b)c)d)Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 3/4d, where d is the separation between the plates of parallel plate capacitor. The new capacitance (C) in terms of original capacitance (C0) is given by the following relation:a)b)c)d)Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.