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A sailor goes 12 km downstream in 48 minutes and returns in 1 hour 20 minutes. The speed of the sailor in still water is:
Correct answer is '12'. Can you explain this answer?
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Most Upvoted Answer
A sailor goes 12 km downstream in 48 minutes and returns in 1 hour 20...
Let the speed of sailor in still water be x kmph.
Speed of current = y kmph
∴ x + y = 
=12/48 × 60 = 15 kmph
and,x − y = 
=12/80 × 60 =9 kmph
Adding these equations,
2x = 15 + 9 = 24
x = 24/2 = 12 kmph
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A sailor goes 12 km downstream in 48 minutes and returns in 1 hour 20...
Given information:
A sailor goes 12 km downstream in 48 minutes and returns in 1 hour 20 minutes.
To find:
The speed of the sailor in still water.
Approach:
To find the speed of the sailor in still water, we need to consider the concept of relative speed and the formula:
Speed of the boat in still water = (Speed downstream + Speed upstream) / 2
Calculation:
Let's assume:
- Speed of the boat in still water = v km/h
- Speed of the current = c km/h
Downstream:
- Distance = 12 km
- Time = 48 minutes = 48/60 hours = 4/5 hours
The speed of the boat downstream can be calculated using the formula:
Speed downstream = (Distance / Time)
Substituting the given values:
Speed downstream = (12 / (4/5)) = (12 * 5/4) = 15 km/h
Upstream:
- Distance = 12 km
- Time = 1 hour 20 minutes = 1 + 20/60 = 1 + 1/3 = 4/3 hours
The speed of the boat upstream can be calculated using the formula:
Speed upstream = (Distance / Time)
Substituting the given values:
Speed upstream = (12 / (4/3)) = (12 * 3/4) = 9 km/h
Speed in still water:
Using the formula:
Speed of the boat in still water = (Speed downstream + Speed upstream) / 2
Substituting the calculated values:
Speed of the boat in still water = (15 + 9) / 2 = 24 / 2 = 12 km/h
Therefore, the speed of the sailor in still water is 12 km/h.
A sailor goes 12 km downstream in 48 minutes and returns in 1 hour 20 minutes.
To find:
The speed of the sailor in still water.
Approach:
To find the speed of the sailor in still water, we need to consider the concept of relative speed and the formula:
Speed of the boat in still water = (Speed downstream + Speed upstream) / 2
Calculation:
Let's assume:
- Speed of the boat in still water = v km/h
- Speed of the current = c km/h
Downstream:
- Distance = 12 km
- Time = 48 minutes = 48/60 hours = 4/5 hours
The speed of the boat downstream can be calculated using the formula:
Speed downstream = (Distance / Time)
Substituting the given values:
Speed downstream = (12 / (4/5)) = (12 * 5/4) = 15 km/h
Upstream:
- Distance = 12 km
- Time = 1 hour 20 minutes = 1 + 20/60 = 1 + 1/3 = 4/3 hours
The speed of the boat upstream can be calculated using the formula:
Speed upstream = (Distance / Time)
Substituting the given values:
Speed upstream = (12 / (4/3)) = (12 * 3/4) = 9 km/h
Speed in still water:
Using the formula:
Speed of the boat in still water = (Speed downstream + Speed upstream) / 2
Substituting the calculated values:
Speed of the boat in still water = (15 + 9) / 2 = 24 / 2 = 12 km/h
Therefore, the speed of the sailor in still water is 12 km/h.
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A sailor goes 12 km downstream in 48 minutes and returns in 1 hour 20 minutes. The speed of the sailor in still water is:Correct answer is '12'. Can you explain this answer?
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A sailor goes 12 km downstream in 48 minutes and returns in 1 hour 20 minutes. The speed of the sailor in still water is:Correct answer is '12'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A sailor goes 12 km downstream in 48 minutes and returns in 1 hour 20 minutes. The speed of the sailor in still water is:Correct answer is '12'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sailor goes 12 km downstream in 48 minutes and returns in 1 hour 20 minutes. The speed of the sailor in still water is:Correct answer is '12'. Can you explain this answer?.
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