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When light of wavelength 248 nm falls on a metal of threshold energy 3.0 eV, the de-Broglie wavelength of emitted electrons is _________ .
(Round off to the nearest integer)
[Use: √3  = 1.73, h = 6.63 × 10-34 Js, me = 9.1 × 10-31 kg; c = 3.0 × 108 ms-1; 1eV = 1.6 × 10-19J]
    Correct answer is '9'. Can you explain this answer?
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    Most Upvoted Answer
    When light of wavelength 248 nm falls on a metal of threshold energy 3...
    Energy incident = hc / λ

    = 0.05 eV × 100 = 5 eV
    Now, using E = ϕ + K.E.
    5 = 3 + K.E.
    K.E. = 2eV = 3.2 × 10-19 J
    For de-broglie wavelength,

    Hence, 

    = 8.72 × 10-10 m
    ≈ 9 × 10-10 m
    = 9
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    The French physicist Louis de-Broglie in 1924 postulated that matter, like radiation, should exhibit a dual behaviour. He proposed the following relationship between the wavelength of a material particle, its linear momentum p and planck constant h.The de Broglie relation implies that the wavelength of a particle should decreases as its velocity increases. It also implies that for a given velocity heavier particles should have shorter wavelength than lighter particles. The waves associated with particles in motion are called matter waves or de Broglie waves.These waves differ from the electromagnetic waves as they,(i) have lower velocities(ii) have no electrical and magnetic fields and(iii) are not emitted by the particle under consideration.The experimental confirmation of the deBroglie relation was obtained when Davisson and Germer, in 1927, observed that a beam of electrons is diffracted by a nickel crystal. As diffraction is a characteristic property of waves, hence the beam of electron behaves as a wave, as proposed by deBroglie.Werner Heisenberg considered the limits of how precisely we can measure properties of an electron or other microscopic particle like electron. He determined that there is a fundamental limit of how closely we can measure both position and momentum. The more accurately we measure the momentum of a particle, the less accurately we can determine its position. The converse is also ture. This is summed up in what we now call the Heisenberg uncertainty principle : It is impossible to determine simultaneously and precisely both the momentum and position of a particle. The product of undertainty in the position, x and the uncertainity in the momentum (mv) must be greater than or equal to h/4. i.e.Q. The transition, so that the de - Broglie wavelength of electron becomes 3 times of its initial value in He+ ion will be

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    When light of wavelength 248 nm falls on a metal of threshold energy 3.0 eV, the de-Broglie wavelength of emitted electrons is _________ .(Round off to the nearest integer)[Use:√3 = 1.73, h = 6.63 × 10-34 Js, me = 9.1 × 10-31 kg; c = 3.0 × 108 ms-1; 1eV = 1.6 × 10-19J]Correct answer is '9'. Can you explain this answer?
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    When light of wavelength 248 nm falls on a metal of threshold energy 3.0 eV, the de-Broglie wavelength of emitted electrons is _________ .(Round off to the nearest integer)[Use:√3 = 1.73, h = 6.63 × 10-34 Js, me = 9.1 × 10-31 kg; c = 3.0 × 108 ms-1; 1eV = 1.6 × 10-19J]Correct answer is '9'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When light of wavelength 248 nm falls on a metal of threshold energy 3.0 eV, the de-Broglie wavelength of emitted electrons is _________ .(Round off to the nearest integer)[Use:√3 = 1.73, h = 6.63 × 10-34 Js, me = 9.1 × 10-31 kg; c = 3.0 × 108 ms-1; 1eV = 1.6 × 10-19J]Correct answer is '9'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When light of wavelength 248 nm falls on a metal of threshold energy 3.0 eV, the de-Broglie wavelength of emitted electrons is _________ .(Round off to the nearest integer)[Use:√3 = 1.73, h = 6.63 × 10-34 Js, me = 9.1 × 10-31 kg; c = 3.0 × 108 ms-1; 1eV = 1.6 × 10-19J]Correct answer is '9'. Can you explain this answer?.
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