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The decomposition of formic acid on gold surface follows first order kinetics. If the rate constant at 300 K is 1.0 × 10-3 s-1 and the activation energy Ea is 11.488 kJ mol-1, the rate constant at 200 K is ___________ × 10-5 s-1
(Round off to the nearest integer)
(Given: R = 8.314 J mol-1 K-1)
    Correct answer is '10'. Can you explain this answer?
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    The decomposition of formic acid on gold surface follows first order k...
    K300 = 10-4, K200 = ?
    Ea = 11.488 KJ mol-1, R = 8.314 J/mole-K
    So,


    = 2.303

    So, 

    = 10 × 10-5 sec-1
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    The decomposition of formic acid on gold surface follows first order kinetics. If the rate constant at 300 K is 1.0 × 10-3 s-1 and the activation energy Ea is 11.488 kJ mol-1, the rate constant at 200 K is ___________ × 10-5 s-1(Round off to the nearest integer)(Given: R = 8.314 J mol-1 K-1)Correct answer is '10'. Can you explain this answer?
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    The decomposition of formic acid on gold surface follows first order kinetics. If the rate constant at 300 K is 1.0 × 10-3 s-1 and the activation energy Ea is 11.488 kJ mol-1, the rate constant at 200 K is ___________ × 10-5 s-1(Round off to the nearest integer)(Given: R = 8.314 J mol-1 K-1)Correct answer is '10'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The decomposition of formic acid on gold surface follows first order kinetics. If the rate constant at 300 K is 1.0 × 10-3 s-1 and the activation energy Ea is 11.488 kJ mol-1, the rate constant at 200 K is ___________ × 10-5 s-1(Round off to the nearest integer)(Given: R = 8.314 J mol-1 K-1)Correct answer is '10'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The decomposition of formic acid on gold surface follows first order kinetics. If the rate constant at 300 K is 1.0 × 10-3 s-1 and the activation energy Ea is 11.488 kJ mol-1, the rate constant at 200 K is ___________ × 10-5 s-1(Round off to the nearest integer)(Given: R = 8.314 J mol-1 K-1)Correct answer is '10'. Can you explain this answer?.
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