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In a right angle triangle, the Hypotenuse is 2.125 times of one of Perpendicular Sides the triangle. The sum of in-radius and that side is 44 cm. find the Circum-radius of the triangle ?
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Problem Statement: In a right angle triangle, the Hypotenuse is 2.125 times of one of Perpendicular Sides the triangle. The sum of in-radius and that side is 44 cm. Find the Circum-radius of the triangle?

Given:

  • Hypotenuse = 2.125 * Perpendicular Side

  • In-radius + Perpendicular Side = 44 cm



To Find:

  • Circum-radius of the triangle



Solution:

  • Let the Perpendicular Side of the triangle be 'a'.

  • Then, the Hypotenuse of the triangle = 2.125 * a

  • Using Pythagoras Theorem, we have:


    • a^2 + b^2 = c^2 (where c is the hypotenuse)

    • a^2 + (2.125a)^2 = c^2

    • a^2 + 4.515625a^2 = c^2

    • c^2 = 5.515625a^2

    • c = 2.35a (approx)


  • The in-radius (r) of the triangle is given by:


    • r = (Perimeter of triangle - Hypotenuse)/2

    • r = (a + 2.125a + c)/2

    • r = (3.125a + c)/2

    • r = (3.125a + 2.35a)/2

    • r = 2.7375a


  • The sum of in-radius and Perpendicular Side is given by:


    • r + a = 44

    • 2.7375a + a = 44

    • 3.7375a = 44

    • a = 11.75 cm (approx)


  • Substituting the value of a in the equation c = 2.35a, we get:


    • c = 27.6625 cm (approx)


  • The Circum-radius (R) of the triangle is given by:


    • R = c/2

    • R = 13.83125 cm (approx)




Answer:

  • Circum-radius of the triangle = 13.83125 cm (approx)

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