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In __________ disk scheduling algorithm, the disk head moves from one end to other end of the disk, serving the requests along the way. When the head reaches the other end, it immediately returns to the beginning of the disk without serving any requests on the return trip.
- a)LOOK
- b)SCAN
- c)C-LOOK
- d)C-SCAN
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
In __________ disk scheduling algorithm, the disk head moves from one ...
Explanation:
C-SCAN (Circular SCAN):
C-SCAN is a disk scheduling algorithm where the disk head moves from one end to the other end of the disk, serving the requests along the way. However, when the head reaches the other end, it immediately returns to the beginning of the disk without serving any requests on the return trip.
Key points about C-SCAN algorithm:
- C-SCAN is a variant of the SCAN algorithm.
- In the C-SCAN algorithm, the disk head moves in a circular manner.
- The head serves all requests in one direction until it reaches the end of the disk, then it returns to the beginning without serving any requests on the way back.
- This approach helps in reducing the average seek time as it avoids the head movement over the entire disk range.
Advantages of C-SCAN algorithm:
- C-SCAN algorithm ensures a more predictable and consistent service time for requests.
- It reduces the overall seek time as the head movement is optimized in a single direction without any backtracking.
- C-SCAN is particularly useful in scenarios where there are a large number of requests and the disk is heavily loaded.
Conclusion:
In conclusion, the C-SCAN disk scheduling algorithm offers efficient and optimized disk access by moving the disk head in a circular manner, serving requests in one direction and returning to the beginning without any interruptions. This helps in minimizing seek time and providing consistent performance in disk scheduling.
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In __________ disk scheduling algorithm, the disk head moves from one ...
In C-SCAN disk scheduling algorithm, the disk head serve the request from ine end to other end but when it reaches to other end it immediately returns to the starting of the disk without serving any request. Refer:Disk Scheduling Algorithms So option (D) is correct.
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In __________ disk scheduling algorithm, the disk head moves from one end to other end of the disk, serving the requests along the way. When the head reaches the other end, it immediately returns to the beginning of the disk without serving any requests on the return trip.a)LOOKb)SCANc)C-LOOKd)C-SCANCorrect answer is option 'D'. Can you explain this answer?
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