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The total time to prepare a disk drive mechanism for a block of data to be read from it is
  • a)
    seek time
  • b)
    latency
  • c)
    latency plus seek time
  • d)
    transmission time
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The total time to prepare a disk drive mechanism for a block of data t...
Seek time is the time taken by the head to move to the correct track and Rotational latency is the time taken by the disk to rotate until the head is over the desired block to read So, the total time to prepare a disk drive mechanism for a block of data to be read from is the sum of both the seek time and the latency. Option (C) is correct.
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The total time to prepare a disk drive mechanism for a block of data t...

Explanation:

Latency:
- Latency is the time it takes for the desired data to rotate under the read/write head.
- It is dependent on the rotational speed of the disk, typically measured in milliseconds.

Seek Time:
- Seek time is the time it takes for the read/write head to move to the correct track on the disk.
- It is also measured in milliseconds.

Latency plus Seek Time:
- The total time to prepare a disk drive mechanism for a block of data to be read from it is the sum of latency and seek time.
- This is because the disk needs to rotate to the correct position and the read/write head needs to move to the correct track before the data can be accessed.

Transmission Time:
- Transmission time refers to the time it takes to actually transfer the data once the disk is ready.

Conclusion:
- Therefore, the total time to prepare a disk drive mechanism for a block of data to be read from it is the sum of latency and seek time.
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The total time to prepare a disk drive mechanism for a block of data to be read from it isa)seek timeb)latencyc)latency plus seek timed)transmission timeCorrect answer is option 'C'. Can you explain this answer?
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