Civil Engineering (CE) Exam  >  Civil Engineering (CE) Questions  >  The Mohr-Coulomb failure criterion, which is ... Start Learning for Free
The Mohr-Coulomb failure criterion, which is defined by shear strength (s) consisting of effective normal stress (σ’), cohesion (c’) and effective angle of friction (ϕ’), is given by,
  • a)
    s = σ’ + c’ tanϕ’
  • b)
    s = c’ tanϕ’ + σ’
  • c)
    s = c’ – σ’ tanϕ’
  • d)
    s = c’ + σ’ tanϕ’
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The Mohr-Coulomb failure criterion, which is defined by shear strength...
Concept:
Shear strength of soil is the capacity of soil to resist shearing stresses.  It can be defined as the maximum value of shear stress that can be mobilized within a soil mass.
Note:
If this value exceeded by the shear stress on any plane or a surface at a point, failure will occur in soil because of the movement of a portion of the soil mass along that particular plane. The soil is then said to fail in shear. Therefore, shear strength generally represented the strength of the soil.
As per Mohr-Coulomb criteria, Shear strength (s) of soil is given as:
s = c' + σ' tanϕ'
Where,
c' = effective cohesion
σ' = effective normal stress
ϕ' = effective angle of friction
Free Test
Community Answer
The Mohr-Coulomb failure criterion, which is defined by shear strength...
Σ') and cohesion (c), can be expressed as:

s = c + σ' tan(ϕ)

where:
- s is the shear strength
- c is the cohesion
- σ' is the effective normal stress
- ϕ is the angle of internal friction

The effective normal stress (σ') is the difference between the total normal stress (σ) and the pore water pressure (u):

σ' = σ - u

The Mohr-Coulomb failure criterion is commonly used in geotechnical engineering to analyze the stability of soil and rock slopes. It describes the relationship between shear strength and normal stress, taking into account the cohesive and frictional properties of the material.

The cohesion (c) represents the shear strength of the material when there is no normal stress acting on it. It is a measure of the material's ability to resist shear forces even in the absence of friction.

The angle of internal friction (ϕ) represents the resistance to shear provided by the frictional properties of the material. It is the angle between the failure plane and the normal stress direction.

By plotting the Mohr-Coulomb failure criterion on a graph, engineers can determine the state of stress at which failure is expected to occur. This information is crucial for designing safe and stable structures, such as retaining walls, foundations, and slopes.
Explore Courses for Civil Engineering (CE) exam

Top Courses for Civil Engineering (CE)

The Mohr-Coulomb failure criterion, which is defined by shear strength (s) consisting of effective normal stress (σ’), cohesion (c’) and effective angle of friction (’), is given by,a)s = σ’ + c’ tan’b)s = c’ tan’ + σ’c)s = c’ – σ’ tan’d)s = c’ + σ’ tan’Correct answer is option 'D'. Can you explain this answer?
Question Description
The Mohr-Coulomb failure criterion, which is defined by shear strength (s) consisting of effective normal stress (σ’), cohesion (c’) and effective angle of friction (’), is given by,a)s = σ’ + c’ tan’b)s = c’ tan’ + σ’c)s = c’ – σ’ tan’d)s = c’ + σ’ tan’Correct answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The Mohr-Coulomb failure criterion, which is defined by shear strength (s) consisting of effective normal stress (σ’), cohesion (c’) and effective angle of friction (’), is given by,a)s = σ’ + c’ tan’b)s = c’ tan’ + σ’c)s = c’ – σ’ tan’d)s = c’ + σ’ tan’Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The Mohr-Coulomb failure criterion, which is defined by shear strength (s) consisting of effective normal stress (σ’), cohesion (c’) and effective angle of friction (’), is given by,a)s = σ’ + c’ tan’b)s = c’ tan’ + σ’c)s = c’ – σ’ tan’d)s = c’ + σ’ tan’Correct answer is option 'D'. Can you explain this answer?.
Solutions for The Mohr-Coulomb failure criterion, which is defined by shear strength (s) consisting of effective normal stress (σ’), cohesion (c’) and effective angle of friction (’), is given by,a)s = σ’ + c’ tan’b)s = c’ tan’ + σ’c)s = c’ – σ’ tan’d)s = c’ + σ’ tan’Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
Here you can find the meaning of The Mohr-Coulomb failure criterion, which is defined by shear strength (s) consisting of effective normal stress (σ’), cohesion (c’) and effective angle of friction (’), is given by,a)s = σ’ + c’ tan’b)s = c’ tan’ + σ’c)s = c’ – σ’ tan’d)s = c’ + σ’ tan’Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The Mohr-Coulomb failure criterion, which is defined by shear strength (s) consisting of effective normal stress (σ’), cohesion (c’) and effective angle of friction (’), is given by,a)s = σ’ + c’ tan’b)s = c’ tan’ + σ’c)s = c’ – σ’ tan’d)s = c’ + σ’ tan’Correct answer is option 'D'. Can you explain this answer?, a detailed solution for The Mohr-Coulomb failure criterion, which is defined by shear strength (s) consisting of effective normal stress (σ’), cohesion (c’) and effective angle of friction (’), is given by,a)s = σ’ + c’ tan’b)s = c’ tan’ + σ’c)s = c’ – σ’ tan’d)s = c’ + σ’ tan’Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of The Mohr-Coulomb failure criterion, which is defined by shear strength (s) consisting of effective normal stress (σ’), cohesion (c’) and effective angle of friction (’), is given by,a)s = σ’ + c’ tan’b)s = c’ tan’ + σ’c)s = c’ – σ’ tan’d)s = c’ + σ’ tan’Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The Mohr-Coulomb failure criterion, which is defined by shear strength (s) consisting of effective normal stress (σ’), cohesion (c’) and effective angle of friction (’), is given by,a)s = σ’ + c’ tan’b)s = c’ tan’ + σ’c)s = c’ – σ’ tan’d)s = c’ + σ’ tan’Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
Explore Courses for Civil Engineering (CE) exam

Top Courses for Civil Engineering (CE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev